1. Introduction and Preliminaries
The well-known Banach’s fixed-point theorem (BFPT) [
1] is the most important basic fixed-point result. Because this principle has numerous applications in various disciplines of mathematics, several writers have generalised, extended, and improved it in a variety of ways by considering various types of mappings or spaces. One such remarkable generalisation was given by Wardowski [
2]. He introduced the notion of
F contraction as follows:
Definition 1. Let be a metric space (MS). A mapping is said to be an F contraction if there exists and such that for all , the following is true:where is the set of all mappings that meets the following criteria: - ()
for all ;
- ()
For any sequence , if and only if
- ()
There exists such that
Theorem 1 ([
2])
. Consider a complete MS and to be an F contraction. Then, is a unique fixed point of ψ, and for every , a sequence is convergent to . In [
3], Secelean demonstrated that condition (
) can be modified with an equivalent and simpler one ((
):
). Following that, Piri and Kumam [
4] established Wardowski’s theorem utilising (
) and the continuity rather than (
) and (
), respectively. Wardowski [
5] later proved a fixed-point theorem for
F contractions when
is treated as a function:
Theorem 2 (Theorem 2.1 of [
5])
. Let be a complete MS and . Let us say that there exist functions and such that the following are true:F satisfies and .
.
for all such that .
Then, has only one fixed point in 𝓏.
From here onward, we denote with the set of all functions satisfying condition .
Recently, other authors demonstrated (in various methods) Wardowski’s original results in the absence of both requirements (
) and (
) (see [
6,
7]). For more on this direction, consult [
8,
9,
10,
11,
12,
13,
14,
15]. Cosentino and Vetro [
16] created a new concept, an
F contraction of the Hardy–Rogers type, and derived the fixed-point theorem. Later, Vetro [
14] expanded the notion of the Hardy–Rogers-type
F contraction by switching
with a function and proposed the notion of a Suzuki–Hardy–Rogers-type
F contraction.
The concept of symmetry is characteristic of a Banach space, which is deeply related to the fixed-point problems [
17] and has importance. Well-known researchers are observing it properly and working on it worldwide. This unwavering interest has been known to stem from the practical application of this area of research to several fields of research. Now, we should recall that symmetry is a mapping on some object
X, which is supposed to be structured onto itself such that the structure is preserved. Saleem et al. [
18] and Sain [
19] provided several ways this mapping could occur. Neugebaner [
17], using the concept of symmetry, obtained several applications of a layered compression–expansion fixed-point theorem in the existence of solutions of a second-order difference equation with Dirichlet boundary conditions.
On the other hand, Bakhtin [
20] developed the concept of
b-metric spaces as a generalisation of metric spaces in 1989 (also see the work of Czerwik [
21]). Articles have been published that address results in
b-metric spaces (see [
22,
23,
24,
25,
26,
27,
28,
29,
30,
31] and some related references therein). We will explain the definition of a
b-metric space again:
Definition 2 ([
21])
. Let 𝓏
be a non-empty set, and let be a certain real number. A mapping is claimed to be b-metric if for any , the following requirements are met:- ()
if and only if ;
- ()
;
- ()
.
The pair is called a b-metric space (b-MS) with a constant .
The preceding definition makes it clear that a
b-MS is standard metric space when
. Nonetheless, the converse is false (see [
32,
33]). It is important to remember that a
b-metric space is not always continuous (see Example 3.3 in [
34]). The lemmas listed below are quite helpful for handling this issue:
Lemma 1 ([
22])
. Let be a b-MS with a constant and be a sequence in 𝓏
such that . Then, for each , we have Lemma 2 ([
35])
. Let be a b-MS with a constant and be a sequence in 𝓏
such that . If is not Cauchy sequence in , then there exist and two sequences and of positive integers such that the following items hold: Proposition 1 (Proposition 3.11 of [
23])
. Let be a b-MS with . If b is continuous in one variable, then it is also continuous in the other. Lukács and Kajántá [
6] refined Wardowski’s theorem in the context of
b-MS and dropped condition
. Following that, several authors demonstrated (through various methods) Wardowski’s original results in the absence of both conditions
and
(see [
7,
36]). Derouiche and Ramoul [
35] recently introduced the notions of the extended
F contraction of the Hardy–Rogers type, extended
F contraction of the Suzuki–Hardy–Rogers type, and generalised
F-weak contraction of the Hardy–Rogers type by employing a relaxed version of condition (
) and eliminating condition (
), and they established some new fixed-point results for such kinds of mappings in the setting of complete
b-metric spaces by using the following lemma:
Lemma 3 (Proposition 3.6 of [
35])
. Let be a b-MS with and ℵ be a certain real number such that . Let be a mapping and be the Picard sequence of based on an arbitrary point . Consider that there exists an increasing function F and such that for each with , the following holds:where , in which , represents nonnegative real numbers satisfying and . Then, . Not long ago, in 2021, Huang et al. [
37] introduced the notion of a convex
F contraction and established some fixed-point results for such contractions in the context of
b-MS.
Motivated by the works in [
35,
37], in this paper, we refine the notion of the convex
F contraction in the setting of
b-MS by introducing the extended convex
F contraction. Our results unify and generalise many existing results in the literature, including those in [
5,
14,
35,
37].
2. Fundamental Results
We start this section by providing the following helpful lemma:
Lemma 4 ([
35])
. Let be a specific real number. Let be a sequence, and let be functions that meet the following requirements:- (i)
for all ;
- (ii)
α is increasing;
- (iii)
for all ;
- (iv)
for all .
Then, .
Consistent with [
35], we have
Let
be a particular real number. We denote with
the family of all functions
which meet the criteria listed below:
Obviously, if
, then Equation (
3) becomes the following:
From here onward, we denote with the set when . Definitively, we have . Additionally, observe that in the sense of standard metric space, it is sufficient to employ the condition that rather than the condition .
Example 1. Consider the function defined by . Then, F is increasing and continuous, and thus .
Example 2. Consider the function defined by . Definitively, , but F does not satisfy condition . Indeed, for any sequence such that , we have More precisely, .
Example 3 ([
35])
. Let be functions defined by the following conditions:- (a)
for each , where is a constant real number;
- (b)
for each ;
- (c)
for each , where .
Then, for all , but .
We now prove the following lemmas, which significantly contribute to the proofs of our results:
Lemma 5. Let be a b-MS with a constant and ℵ be a given real number such that . Let be a mapping and be the Picard sequence of based on an arbitrary point . Assume that there exists an increasing function F and such that for all with , the following is true:where . Then, . Proof. Start with
. If
for some
, then the proof is conclusive. Therefore, assume that
for all
. By applying the inequality in Equation (
5), we have for all
By virtue of the fact that
for all
, we have
Since
F is increasing, then
which further implies that
Hence,
is a convergent sequence. Now, from Equations (
6) and (
7), we have
By taking
and
for all
, the inequality in Equation (
8) can be written as
As
F is increasing, then in light of the inequality in Equation (
9), and using the fact that
, it is clear that all of Lemma 4’s criteria with
are satisfied. Thus,
. □
Remark 1. Lemma 5 greatly extends and improves Lemma 3. Indeed, let all hypotheses of Lemma 3 hold true and be a Picard sequence of based on an arbitrary . Assume that for all and for all . Then, from Equation (2), for all , we have By letting , the inequality in Equation (10) turns into Equation (5). Hence, by using Lemma 5, we have . Lemma 6. Let be a b-MS with a constant and be a mapping that satisfies Equation (
5)
for an increasing function F and . If , then for every , the sequence is a Cauchy sequence. Proof. Start with
. Choose an arbitrary point
, and construct a Picard sequence
for all
. If
for some
, then
Hence,
is a Cauchy sequence. Assume that
for all
and
for all
. Then, we can apply the contractive condition in Equation (
5). Hence, we obtain the following for all
:
Hence, from Lemma 5, we have
Now suppose, on the contrary, that
is not a Cauchy sequence. Then, from Equation (
12) and the first item of Lemma 2, there exist
and two sequences
and
of positive integers such that the following item holds:
Thus, we infer that there exists
such that
is bounded for all
and thereby has a convergent subsequence. It follows that there exist a real number
and a subsequence
of
such that
with
On the other hand, using condition
, we obtain the following for all
:
This leads to
for all
. By letting the lower limit be
in Equation (
16) and using Equation (
12), we obtain
As a result, there exist
such that
Therefore, by applying the contractive inequality in Equation (
5), for all
, we obtain
In addition, by using condition
, for all
, we have
Using Equation (
20), the monotonicity of
F, and
, for all
, we obtain
Now, by combining Equation (
21) with Equations (
13) and (
17), and by virtue of the fact that
, we obtain
The preceding inequality implies that
which is a contradiction with Equation (
3). This contradiction shows that
is a Cauchy sequence. □
3. Fixed-Point Theorems
Definition 3. Let be a b-MS with a constant . A mapping is said to be an extended convex Wardowski contraction (or extended convex F contraction) if there exist , and such that for all , the following is true: Remark 2. If F is an increasing function, then Definition 3 implies that every extended convex F contraction satisfies the conditionfor all with . Theorem 3. Let be a complete b-MS with a constant and be an extended convex F contraction for . Assume that . Then, has a unique fixed point in 𝓏.
Proof. Let
be a Picard sequence based on an arbitrary
. If
for some
, then
is a fixed point of
, and the proof is conclusive. Therefore, assume that
for all
. Then, we have
By using the inequality in Equation (
22) with
and
, for all
, we obtain
which is the inequality in Equation (
5). Therefore, by virtue of
and Lemma 5 with
, we have
Since
, from Lemma (6) with
, we conclude that
is a Cauchy sequence. With the completeness of
,
converges to some point
; that is, we have
Next, we show that
is a fixed point of
. Suppose, on the contrary, that
. Then, from Equation (
27), there exists
such that
On the other side, from
, we have
The inequalities in Equations (
28) and (
29) yield
for all
. Now, owing to Equation (
23) with
and
, for all
, Equation (
29) gives
which is a contradiction. Hence,
.
Lastly, we prove that
has a maximum of one fixed point. Assume that
and
are two distinct fixed points of
. Then, we have
From Equation (
22), we obtain
The inequality in Equation (
32) implies that
, which is a contradiction, and the proof is conclusive. □
Remark 3. Observe that in Theorem 3, conditions and are omitted. In addition, the strictness of the monotonicity of F is not considered.
Moreover, Theorem 3 gives the answer to Problem 1 in [37], as conditions and are not used to prove Theorem 3. Since a standard metric space is a b-MS for , then by virtue of Theorem 3, we obtain the following:
Corollary 1. Let be a complete MS and . If there exist , , and such that for all with , the following is true:then has only one fixed point in 𝓏. Remark 4. Note that in Corollary 1, conditions , , and are omitted. Furthermore, the strictness of the monotonicity of F is not considered, and is weakened to the condition . Additionally, by using in Equation (33), we recover Equation (1), and thus Corollary 1 significantly enhances and broadens Theorem 2 in [5]. Example 4. Let be endowed with the Euclidean metric b. Then, is a complete b-MS with . Define the mapping as follows: Define and for all . Then, and . Consider . Then, t the following cases arise:
Case-I:
If and , then Case-II:
If and , then Case-III:
If and , then Case-IV:
If and , then
Hence, in all cases, is an extended convex F contraction for . In addition, note that for and . Thus, all of the requirements for Theorem 3 are met, and zero is the only fixed point of .
Remark 5. Note that in Example 4, if for any sequence , we have , then . Thus, F does not satisfy conditions () or (), and .
Remark 6. In Example 4, for all cases, is an extended F contraction (see [35]) for , , and . However, , and . Therefore, Theorem 3.13 in [35] is not applicable to Example 4. Theorem 4. Let be a complete b-MS with a constant and be a mapping. If there exist and such that for all with , we haveand if , then has a unique fixed point in 𝓏. Proof. Let
be a Picard sequence based on an arbitrary
. If
for some
, then
is a fixed point of
, and the proof is conclusive. Therefore, assume that
for all
. Then, we have
Thus, by using the inequality in Equation (
34) with
and
, for all
, we obtain
By using condition
, Equation (
35) implies
By using
and
, the inequality in Equation (
36) turns into Equation (
5). Therefore, by virtue of
and Lemma 5 with
, we have
If
, then for
, we have
. Thus, by using Lemma 6,
is a Cauchy sequence, and consequently,
converges to some point
; that is, we have
Now, if
, then by using Equation (
34), we have
By letting
in the inequality in Equation (
39), we obtain
which is a contradiction, and consequently,
.
Next, if
has two fixed points
and
such that
, then by using Equation (
34), we obtain
which is a contradiction, and this completes the proof. □
Corollary 2. Let be a complete MS and be a mapping. If there exist and such that for all with , it is true thatthen has a unique fixed point in 𝓏. Theorem 5. Let be a complete MS and be a mapping. If there exist and such that for all with , it is true thatwhere , , and , then assume either or holds, and has a unique fixed point in 𝓏. Proof. First, we prove that there is at most one fixed point of
in 𝓏. Assume that
are fixed points of
with
. Now, if
, by using
and
in Equation (
41), we have
which is a contradiction since
, and hence
. On the other hand, if
, by using Equations (
3) and (
41), we obtain
which is a contradiction, and thus
.
Let
be a Picard sequence based on an arbitrary
. If
for some
, then
is a fixed point of
, and the proof is conclusive. Therefore, when assuming that
for all
, we then have
If
, then by using the inequality in Equation (
41) with
and
, for all
, we obtain
By using a triangular inequality, Equation (
42) implies that
By using
,
, and
, the inequality in Equation (
42) turns into Equation (
5).
If
, then by using the inequality in Equation (
41) with
and
, for all
, we obtain
By using
,
, and
, the inequality in Equation (
44) turns into Equation (
5).
Therefore, in either case, by virtue of Lemma 5 with
and
, we have
In addition, by using Lemma 6,
is a Cauchy sequence, and consequently,
converges to some point
; that is, we have
In the following, we show that
is a fixed point of
. Suppose, on contrary, that
. If
for infinite values of
, then the sequence
has a subsequence that converges to
, and the uniqueness of the limit implies
. Then, we can assume that
for all
. Now, by using Equations (
3) and (
41), we obtain
By letting
in the inequality in Equation (
47), we obtain
which is a contradiction, and hence
. □
Remark 7. Theorem 5 is Theorem 3.13 in [35] for the case where , but here, we re-proof this theorem by using Lemmas 5 and 6 and the note from Remark 3 that Lemma 5 greatly extends and improves Lemma 3. Moreover, Theorem 5 improves Theorem 1 in [14] as condition is omitted and is weakened to the condition that . 4. Application to the Theory of Iterated Function Systems
Let
be a
b-MS with a constant
. We denote with
and
the family of all nonempty subsets of 𝓏 and the family of nonempty and compact subsets of 𝓏, respectively. For
, define
, and
as follows:
Then,
is a complete
b-MS, provided that
is complete [
38].
Lemma 7 ([
38])
. Let be a b-MS with a constant and . Then, for each , there exists such thatIf is a b-MS, and is a continuous b metric, then for each , there exists such that Consider a finite family of continuous operators
. The system
is called an iterated functions system (IFS) [
39]. Define the fractal operator
generated by the IFS
with the following relation:
Then, a nonempty compact subset of 𝓏 is said to be a self-similar set or a fractal with respect to the IFS if and only if it is a fixed point for the associated fractal operator (i.e., ). Note that is a complete b-MS if is complete and is known as a fractal space. Now, we will prove the following lemma:
Lemma 8. Let be a b-MS with a constant such that b is a continuous functional on . If is an extended convex F contraction for , and for all , then is also an extended convex F contraction for the same , and for all ; that is, there exist and such that for all , the following holds.where for all , . Proof. Let
such that
and
b be a continuous functional on
. Choose an arbitrary element
. Then, by the compactness of
G, there is
such that
By using Lemma 7 and the inequality in Equation (
49), we obtain
Since
was arbitrary, we have
and hence
Since
is an extended convex
F contraction for
, and
for all
, we have
Therefore, by using the inequalities in Equations (
53) and (
55), we obtain
Hence, we obtain
which further implies
for
. □
Theorem 6. Let be a complete b-MS with a constant such that b is a continuous functional on , is an extended convex F contraction for , and for all . Assume that . Then, the fractal operator has a unique fixed point .
Proof. Let be a complete b-MS. Then, is a complete b-MS. Since is an extended convex F contraction for , and for all , then under Lemma 8, the fractal operator is also an extended convex F contraction for , and for all . Hence, all conditions for Theorem 3 hold true, and has a unique fixed point . □
Finally, we pose the following problems: