In this section, a combinatorial criterion for the calculation of the fractional edge dimension of any graph is proposed. As an application, the fractional edge dimension of the friendship graph and the circulant graph is computed.
The following main result of this section gives the combinatorial criterion for calculating the fractional edge dimension of any graph.
3.2. Fractional Edge Dimension of Circulant Graph
From now on, let
be a circulant graph with
and
, where
. Since the class of circulant graphs is vertex transitive, then label the arbitrary vertex as
and other vertices accordingly. The set of edges of
G can be partitioned as
based on labels. If
n is even,
,
,
, and
(see
Figure 2). If
n is odd,
,
,
, and
(see
Figure 3). Note that the subscript of vertices is taken only over modulo
n. Let
denote
. In the following lemmas, the cardinalities of the edge resolving neighborhoods of different pairs of distinct edges in
G are computed, followed by the computation of the fractional edge dimension,
, of
G.
The following lemma gives the fractional edge dimension of .
Lemma 3. If , then .
Proof. Let
and
be the vertex and edge set of
G, respectively (see
Figure 3). Due to symmetry, the edge resolving neighborhoods of some specific pairs of edges are described as:
. Clearly, the set of cardinalities of these edge resolving neighborhoods is . Furthermore, , where i is odd and . The index of vertices are taken over modulo 7. Thus, . Additionally, , where . Using the criterion given in Theorem 5, define by , with as the minimum edge resolving function of G. Hence, . □
The edge resolving neighborhoods of minimum cardinalities in G are given in the following result.
Lemma 4. If G is a circulant graph of order , then Furthermore , where i is even and .
Proof. Since
therefore,
If i is even such that , then
The subscripts of vertices are taken over modulo n.
Similarly, if i is even such that , then
The subscripts of vertices are taken over modulo n. This shows . □
In the following lemma, the cardinality of the edge resolving neighborhood of a pair of edges is calculated.
Lemma 5. If G is a circulant graph of order , then and
, where .
Proof. Since that shows and using Lemma 4. □
Next, edges , where if , or if otherwise, are considered. The cardinalities of their edge resolving neighborhoods are computed.
Lemma 6. Let G be a circulant graph of order .
- 1.
If and , then ;
- 2.
If and , then .
Furthermore, , where .
Proof. - 1.
If and , then which implies .
- 2.
If and , then
This shows .
follows from Lemma 4. □
In the following lemma, the edges are considered.
Lemma 7. If G is a circulant graph of order , then .
Furthermore, , where .
Proof. Since
This implies . Clearly, using Lemma 4. □
In the following lemma, the cardinalities of edge resolving neighborhoods of pairs of edges are computed.
Lemma 8. Let G be a circulant graph of order . If n is odd and , or if n is even and , then . Furthermore, , where .
Proof. If is odd and , then
If is even and , then
Combining the cardinalities of the expressions above, . Moreover, is straight forward using Lemma 4. □
Now, The pairs of edges , where accordingly if are considered. The cardinalities of their edge resolving neighborhoods are computed.
Lemma 9. Let G be a circulant graph of order . If n is odd, then with or . Additionally, , where .
Proof. For ,
If or , then . This implies . Using Lemma 4, follows directly. □
Now, consider edges , with an even n.
Lemma 10. Let G be a circulant graph of order . If n is even, then , where .
Proof. If is even, then
Clearly,
Furthermore, using Lemma 4. □
In the following lemma, the cardinalities of the edge resolving neighborhoods of pairs of edges with are computed.
Lemma 11. Let G be a circulant graph of order . If n is even and , then , where .
Proof. If is even and , then
This implies using Lemma 4. □
In the following lemma, the edge resolving neighborhoods of pairs of edges with are considered.
Lemma 12. Let G be a circulant graph of order . If n is even and , then , where .
Proof. If is even and , then
This implies .
Similarly, for , .
For ,
This implies .
For , which shows .
For ,
This implies ,with . Combining the cardinalities of all these edge resolving neighborhoods, with . Thus, , where using Lemma 4. □
In the following lemma, the edge resolving neighborhoods of pairs of edges with are considered for odd n.
Lemma 13. Let G be a circulant graph of order . If n is odd and , then , where .
Proof. For ,
For ,
For , ; for ,
Combining the cardinalities of all these edge resolving neighborhoods implies
with . Using Lemma 4, , where . □
In the following theorem, the fractional edge dimension of is calculated.
Theorem 6. If and , then Proof. From Lemmas 4 to 13,
with
,
with
for an even
n and
for an odd
n. Additionally,
,
. Thus, using Theorem 5, a minimum edge resolving function
is defined by
for all
of
G. Hence,
□