Prospective Mathematics Teachers Understanding of Classical and Frequentist Probability
Abstract
:1. Introduction
2. Theoretical Background
2.1. Classical and Frequentist Views of Probability
Wherefore, if we constitute a fraction whereof the numerator is the number of chances whereby an event might happen, and the denominator the number of all the chances whereby it may either happen or fail, that fraction will be a proper definition of the probability of happening (p. 1).
Probability is thus simply a fraction whose numerator is the number of favourable cases and whose denominator is the number of all cases possible [9], p. ix.
It makes use of an implicit assumption of equal likelihood of all single outcomes of the sample space. It is an a priori approach to probability in that it allows calculations of probabilities before any trial is made [18], p. 41.
2.2. The Education of Mathematics Teachers
2.3. Relating Different Views of Probability
- Randomness: (1) making deterministic predictions; (2) deterministic predictions qualified with probabilistic language; (3) recognising that the outcome cannot be predicted with accuracy; (4) although the outcome cannot be predicted with accuracy, recognising the stability of the frequency in the long run.
- Variability: (1) not considered; (2) thinking that differences between specified and observed frequencies are always significant regardless of sample size; (3) considering a difference to be significant in a small sample but not in a large sample; (4) understanding the relationship of variability with sample size.
- Independence: (1) thinking that successive results depend on the previous outcomes; (2) the result depends on whether the sample is representative; (3) using models to determine a possible result; (4) recognising independence.
3. Materials and Methods
4. Results
4.1. Estimating the Number of White and Black Balls in the Urns
- Correct. When 3 white and 7 black balls in the first urn and 5 balls of each colour in the second urn are estimated from the relative frequency, by correctly relating the classical and frequentist approaches to probability.
- Providing an interval of values. For one or both urns an interval of values that includes the correct answer is given. For example, “in box A there are between 3 and 4 white balls and between 6 and 7 black balls” (P18). This answer is incorrect, as can be deduced by considering that the mean and standard deviation in a binomial distribution B (n, p) are respectively μ = np; σ = √npq, where n is the number of trials, p is the probability of success, and q the probability of failure. If urn A is assumed to have 3 white balls, the number of white balls obtained in 1000 draws can be modelled by a binomial distribution B (0.3, 1000), with μ = 300 and σ = 14.5; and if urn A contains 4 white balls, it is modelled by the binomial distribution B (0.4, 1000), with μ = 400 and σ = 15.5. By typifying the observed number of white balls in each of the two assumptions, we obtain Z = 1.65 for the urn with 3 white balls and Z = −4.9 for the urn with 4 white balls. While the first value of the standard normal distribution N (0, 1) is acceptable, the second is too far away from the mean, and would lead us to reject the solution of 4 white balls, as the data are very unlikely with such a composition of the urn.
- Indicating only that there are fewer white balls than black balls in urn A, and therefore failing to relate the relative frequency of results to the composition of the urn, i.e., not linking the frequentist estimate of the probability obtained from the 1000 draws to the theoretical probability of obtaining each colour, when defined in the classical sense.
- Incorrectly estimating the number of balls of each colour; for example, replying that there are 3 white balls and 4 black balls in urn A, so that the total number of balls is different from 10, or else indicating that the number of balls in each urn cannot be known.
4.1.1. Correct Justifications
- Estimating the probability by analysing the ratio between the numbers of black and white balls in the 1000 extractions, and approximating the number of black and white balls in the urn. This is a correct justification, based on proportional reasoning, which is an essential component of probabilistic reasoning [39].P31: (3,7) and (5,5) but it is not certain. Urn A: Based on the results we could assume a direct relationship between the number of times a colour is drawn and the number of balls inside the urn. A relationship B/W→7/3. Urn B: the same as in A. Ratio B/W → 5/5.
- Estimating the probability value by computing the relative frequency or percentage of balls of each colour in 1000 outcomes, and then determining the expected number of balls of each colour by multiplying the estimated probability by 10 (number of balls in the urn). Finally, rounding the number of balls to the nearest integer:P2:
- Some students also set up and solved an equation by equalling the ratio of black and white balls in the results and inside the urn. They were working at the algebraic level [40], since they used the linear function and dealt with equations in which they found the unknown value, while, in the two previous categories, the students worked at the arithmetic level. Finally, the result must be rounded, although some students did not express this step explicitly. For example:P32:
- Convergence of the proportion or of the sample mean to the population proportion or quoting the LLN. Sometimes, the relationship between the frequentist and classical approach to probability was re-emphasised by recalling the LLN, which states the conditions of convergence of the relative frequency to the theoretical probability (see example P36). A different way of expressing the idea that the relative frequency over a long series of trials (frequentist approach) tends to the theoretical probability (classical approach) is to use the idea of sampling. The composition of balls defines a finite population in each urn and the series of outcomes constitute a sample of 1000 elements, taken with replacement from that population. The proportion of balls of a colour in the urn is a parameter in the population, while the sampling proportion is an unbiased estimator of the population proportion.P36. According to the law of large numbers, when an experiment is performed a sufficiently large number of times, the probability of an event stabilises.P25. The sample mean converges to the population mean; the sample mean is an unbiased estimator of the population mean.
4.1.2. Incorrect or Incomplete Justifications
- They simply answered based on the observed results without being able to estimate the probability. They pointed out that, apparently, the results indicated that there were more or an equal number of balls of one colour than of another. These students did not provide a specific composition for the urns, since they could not relate the relative frequency in the 1000 experiments to an estimate of the number of black and white balls in the urns.P5: I believe that there are more black balls than white balls in urn A, because when drawing 1.000 balls, 676 were black. In the second urn, the number of black and white balls is more similar, so I think there are approximately the same number of each colour.
- Incorrect application of classical probability, by interpreting the experiment outcomes as favourable and possible cases. These prospective teachers failed to understand the difference between event (element of the experiment sample space) and outcome (event that occurred in each trial). Some participants, such as P80, offered a solution that exceeded the total of 10 balls in the urn. In other cases, such as P105, they explained that they did not calculate the probability because they did not know the number of favourable cases.P80: I think that in box A there are about 324 white balls and about 676 black balls. I believe that in box B there are about 510 white balls and about 490 black balls. I can’t know the exact numbers, but it seems reasonable to assume that the values will be similar to these, when assuming that the draws are random. Therefore, the results of the draws and the probability distribution they yield reflect the distribution of balls in the urns.P105: I don’t know how to calculate the number of balls. Not knowing the number of favourable events, I don’t know how to calculate the probability. Besides, by putting the ball back in the urn, the number of possible events is not reduced.
- Equiprobability bias. This biased reasoning arose when the participant suggested that any composition was possible, because we dealt with a random experiment, so that any outcome had the same probability. These participants explicitly showed the equiprobability bias, described by Lecoutre [36], in which it is assumed that any outcome of a random experiment is equiprobable. Consequently, these participants thought that the given results could be obtained with any composition of the urn, and that an estimation of the number of balls was impossible. They failed to link the two approaches to probability.P57. Assuming that we obtain 5 white balls and 5 black balls, the sample will always be different, since it is possible to pick up a ball and leave it, and select the same one again. Therefore, it is not feasible to deduce how many white or black balls there are in the urn.P98: There might be any number of black and white balls. There can be 1 black and 9 white balls or vice versa as each time one is picked up it is replaced. Or there can be 5 and 5 of each colour.
- The number of trials is high enough. Some participants added the explicit description of the experiment properties, which demonstrated their high knowledge of the mathematical content. One of these properties is the high number of trials, which sufficiently justifies the estimation of probability from the relative frequency, i.e., the application of the frequentist approach. Thus, the understanding of the LLN, which according to Ireland and Watson [24] is the main obstacle to linking the two approaches to probability, was overcome.P68: Since there is a large number of attempts, I assumed that the results will tend to approximate to the actual probability of getting a white ball or a black ball in each urn.
- Independence of results in repeated trials, a property required to apply the frequentist definition of probability [41]. This requirement is fulfilled in the proposed situation because sampling with replacement was used. In the following example, A47 described the two properties mentioned above; although he did not explicitly refer to the classical and frequentist views of probability, he implicitly related them in his answer.P47: Urn A: 3 white and 7 black; Urn B: 5 white and 5 black. Since there were many extractions and because they are independent (the ball is always returned to its place) we have obtained the probability of obtaining a white ball and a black ball in each urn, because the large number of attempts tends to approach to what really happens.
4.2. Assigning Probability in New Experiments
- Correct answer. The subject uses the urn model that he/she has constructed in Task 1a (3 black and 7 white balls in urn A and 5 of each colour in urn B) to assign the probability of obtaining one black ball in each urn in the next draw. Consequently, in urn A he assigns the probability 7/10 (or its decimal or percentage expression) to obtain a white ball. Similarly in urn B he assigns a probability ½.
- Partly correct answer, giving only the probability of getting black balls in one urn, but taking into account the estimated number of balls of each colour in the urn constructed in Task 1a. Basically the answer is similar to the previous one, although not all calculations are completed.
- Incorrect answer. The student uses only the results of the 1000 experiments to re-obtain a frequency estimate of the probability, without taking into account that the extraction will be made from an urn with only 10 balls. The construction of the urn involved a modelling process [22], which started from reality (the results observed in the 1000 drawings) and then, simplified this reality to accept certain hypotheses (the total number of balls in each urn is 10; the relative frequency will be close to, but not exactly equal to, to the theoretical probability). The last step in the modelling process is to work with the mathematical model, in this case, to calculate the probability from the assumed composition in the urn. Students who gave this answer built the model, but were unable to use it to answer the new questions.
- Suggesting that the requested probability cannot be computed or not answering this question. Therefore, again, the modelling process was not completed and the two approaches to probability were not connected.
- Correct, basing the argument solely on the estimated composition of the urns and the model built in Task 1, while applying the classical probability approach. The answer is not affected by the last 10 trials.P102: Given that the urns are the former, and the probability of drawing a white ball in urns A and B was 0.3 and 0.5 respectively, you would choose urn B, as the probability is higher.
- Correct, using the determined composition of the urns, as well as the 10 new results. For these participants, the argument was also supported by the model of urns constructed, and the participants giving this answer also alluded to the last 10 results, by comparing them with the greater evidence provided by the 1000 drawings which constitute a larger sample size.P127: As we saw in the first question, the probability of drawing a white ball in urn A is 1/3 and in urn B, 1/2. Therefore, there will be a greater chance of drawing a white ball in urn b, regardless of the results obtained in this last table, since only 10 extractions are taken into account now, and 1000 in the previous questions.
- Partially correct, when using the data from the 1000 draws in task 1, but not the composition of the urns. Although the answer would be correct if the students had not previously constructed the urn models, in this response the two approaches to probability were not completely linked. Thus, instead of considering the theoretical probability 3/10 and 7/10 in urn A, the participant was guided by the relative frequency of outcomes in the experiment, not clearly differentiating between relative frequency and probability, which is a problem described by Chaput et al. [22].P18: Urn A → P (white) = 0.324; Urn B → P(white) = 0.51. The previous sample (item 1) is larger, more representative. Therefore, I would choose urn B.
- Partially correct, by using the data from the 1010 extractions, but not the composition of the urns. As above, the subject used the relative frequency, which is an estimate of the theoretical probability, and not the value of the theoretical probability given by the composition of the urn. The difference is that the relative frequency calculation is adjusted by adding the results of the 10 new trials.P4: In this case, since we use the same previous urns, we already have 10 more outcomes. I would choose urn B, since PA (white) = 329/1010, and PB (white) = 517/1010.
- Incorrect. Participants who relied solely on the 10 results given in Task 2, without taking into account the estimated composition of the urns in Task 1 or the 1000 results provided in Task 1.P23: I would choose urn B because out of the 10 draws, 7 balls were white, while in urn A only 5 were white. This leads to the conclusion that the probability of drawing a white ball from urn B is higher.
- Other errors, which indicate biases in the participants’ reasoning. Thus, P29 suggested that a decision cannot be made because we use sampling with replacement, which manifests an equiprobability bias [36]. In another example, P124 showed a positive recency bias [35], consisting of assuming that the trend of a short series of outcomes will continue; this participant reasoned at the lowest level of understanding independence in Heitele’s model [31].P29: No matter the urn I select, as the balls are returned to the urn.P124: Urn B, as we see that the while ball is on a run.
5. Discussion and Implications for Teacher Education
Author Contributions
Funding
Institutional Review Board Statement
Informed Consent Statement
Data Availability Statement
Conflicts of Interest
References
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Number of White and Black Marbles | Percentage |
---|---|
Correct: Urn A: (3w,7b), Urn B: (5w,5b) | 71.9 |
Providing an interval of values for each urn | 5.8 |
Urn A: More black marbles | 5 |
Incorrect values or anything is possible | 10.8 |
No response | 6.5 |
Justifications | Percentage | |
---|---|---|
Correct | Ratio between black and white results | 13.0 |
Frequentist estimation of probability | 20.1 | |
Setting up and solving an equation | 7.2 | |
Convergence of sample proportion/mean or LLN | 5.0 | |
Partly correct | Basing on experimental results, correct | 22.3 |
Incorrect | Basing on experimental results, incorrect | 12.2 |
Not able to estimate probability or misapplying classical probability | 5.8 | |
Equiprobability bias | 2.2 | |
Do not justify or confuse justification | 12.2 |
Justification | Percentage | |
---|---|---|
Correct | Using the urn composition | 38.1 |
Partly correct | Only compute one probability | 7.9 |
Incorrect | Do not take into account the urn composition | 36.0 |
Suggest it is not possible to compute or do not compute | 18.0 |
Responses | Percentage | |
---|---|---|
Correct | Urn B | 84.2 |
Incorrect | Urn A | 2.9 |
Any of them | 4.3 | |
No response | 8.6 |
Justifications | Percentage | |
---|---|---|
Correct | Basing on the composition of urns (Task 1) | 13.7 |
Using the urn composition and the last 10 results | 17.3 | |
Partly correct | Using the 1000 results only | 6.5 |
Using the 1010 results | 1.4 | |
Incorrect | Using only the last 10 results | 41.7 |
Other errors or biases | 11.5 | |
Do not justify | 7.9 |
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Batanero, C.; Begué, N.; Álvarez-Arroyo, R.; Valenzuela-Ruiz, S.M. Prospective Mathematics Teachers Understanding of Classical and Frequentist Probability. Mathematics 2021, 9, 2526. https://doi.org/10.3390/math9192526
Batanero C, Begué N, Álvarez-Arroyo R, Valenzuela-Ruiz SM. Prospective Mathematics Teachers Understanding of Classical and Frequentist Probability. Mathematics. 2021; 9(19):2526. https://doi.org/10.3390/math9192526
Chicago/Turabian StyleBatanero, Carmen, Nuria Begué, Rocío Álvarez-Arroyo, and Silvia M. Valenzuela-Ruiz. 2021. "Prospective Mathematics Teachers Understanding of Classical and Frequentist Probability" Mathematics 9, no. 19: 2526. https://doi.org/10.3390/math9192526
APA StyleBatanero, C., Begué, N., Álvarez-Arroyo, R., & Valenzuela-Ruiz, S. M. (2021). Prospective Mathematics Teachers Understanding of Classical and Frequentist Probability. Mathematics, 9(19), 2526. https://doi.org/10.3390/math9192526