Left Riemann–Liouville Fractional Sobolev Space on Time Scales and Its Application to a Fractional Boundary Value Problem on Time Scales
Abstract
:1. Introduction
2. Preliminaries
- In Definition 1, we put (i.e., if has a maximum t) and (i.e., if has a minimum t), where ∅ denotes the empty set.
- If , we say that t is right-scattered, while if , we say that t is left-scattered. Points that are right-scattered and left-scattered at the same time are called isolated.
- If and , we say that t is right-dense, while if and , we say that t is left-dense. Points that are right-dense and left-dense at the same time are called dense.
- The graininess function is defined by
- The derivative makes use of the set , which is derived from the time scale as follows: If has a left-scattered maximum M, then ; otherwise, .
- f is Δ-differentiable on and .
- The equality
- X is bounded;
- For any given , there exists such that , implies for all .
3. Some Fundamental Properties of Left Riemann–Liouville Fractional Operators on Time Scales
- If and , then
- If and , then
- For Caputo fractional derivatives, if and , then
- It follows from Definition 7 and Fubini’s theorem on time scales that
- It follows from Definition 8 and Fubini’s theorem on time scales that
- It follows from Definition 9, Fubini’s theorem on time scales and Theorem 1 that
4. Fractional Sobolev Spaces on Time Scales and Their Properties
- By we denote the set of all functions possessing representation with and .
- It is easy to see that Theorem 20 implies that for any , f has the left Riemann–Liouville derivative iff ; that is, f has the representation with .
- If and , then and, consequently,
- If and , then is the set of all functions belong to that satisfy the condition .
- According to , we can consider with respect to the norm
- It follows from and that is continuously immersed into with the natural norm .
- for each , is Δ-measurable in t;
- for Δ, almost every , is continuously differentiable in .
5. An Application
- there are constants such that ;
- there exists an such that .
- If and , then is a critical value of φ.
- If there exists such that and , then .
- is measurable and continuously differentiable in x for and there exist , such thatfor all and .
- There are two constants , such that
- as uniformly for .
- satisfies the condition in . The argument is as follows: Let be a sequence such thatCombining with , we obtain thatThen, combining with and proof by contradiction, we know that is bounded in .Because is a reflexive Banach space (Theorems 25 and 26), going if necessary to a subsequence, we can assume in . As a result, in view of as and the definition of weak convergence, one seesFurthermore, it follows from (20), (23), and Remark 7 that is bounded in and , as . Therefore, there is a constant such thatFurthermore, it follows from the boundedness of in thatConsidering (2.10) in [58], we can find two positive constants , such thatWhen , with an eye to Proposition 2 and , one obtainsWhen , taking (41) into account, one obtainsTherefore, satisfies the condition in .
- satisfies the condition in Lemma 5, which can be explained by the following:Taking into account, we can find two positive constants and such that
- satisfies the condition in Lemma 5. Here are some reasons why:For , and , letIn view of , when , one obtainsIn addition, taking the expressions of and in (50) into account, we can easily obtain the result that satisfiesTherefore, when , we haveSo, for and , together with , one obtainsSo, one getsTherefore, taking large enough and letting , we have . As a consequence, also satisfies the condition in Lemma 5.
- There are a constant and a function such that
- There is an open interval and three constants , such that
- (1)
- is bounded from below in , which can be explained by the following:Since , (53) yields as . Consequently, is bounded from below in .
- (2)
- satisfies the condition in . The argument is as follows:Let be a sequence such that (31) holds. So, together with the proof by contradiction and (53), we can easily see that is bounded in . The remainder of proof is similar to the proof of Step 1 in Proof of Theorem 29. We omit the details.Consequently, combining with Lemma 6, and in Proof of Theorem 30, one gets , which is a critical value of . In other words, there is a critical point such that .
- (3)
- , for the following reasons:Because of , (54) implies for that is small enough. Therefore, .
- There are a constant and a function such that
6. Conclusions
Author Contributions
Funding
Institutional Review Board Statement
Informed Consent Statement
Data Availability Statement
Conflicts of Interest
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Hu, X.; Li, Y. Left Riemann–Liouville Fractional Sobolev Space on Time Scales and Its Application to a Fractional Boundary Value Problem on Time Scales. Fractal Fract. 2022, 6, 268. https://doi.org/10.3390/fractalfract6050268
Hu X, Li Y. Left Riemann–Liouville Fractional Sobolev Space on Time Scales and Its Application to a Fractional Boundary Value Problem on Time Scales. Fractal and Fractional. 2022; 6(5):268. https://doi.org/10.3390/fractalfract6050268
Chicago/Turabian StyleHu, Xing, and Yongkun Li. 2022. "Left Riemann–Liouville Fractional Sobolev Space on Time Scales and Its Application to a Fractional Boundary Value Problem on Time Scales" Fractal and Fractional 6, no. 5: 268. https://doi.org/10.3390/fractalfract6050268
APA StyleHu, X., & Li, Y. (2022). Left Riemann–Liouville Fractional Sobolev Space on Time Scales and Its Application to a Fractional Boundary Value Problem on Time Scales. Fractal and Fractional, 6(5), 268. https://doi.org/10.3390/fractalfract6050268