1. Introduction
Strong theoretical visions via fractional calculus are some of the most significant ways to describe natural models. To our knowledge, fractional calculus is a vast field with many kinds of fractional differential operators and corresponding integrals. For examples, see [
1,
2,
3]. One way to explain the importance of fractional calculus is by generating classical calculus, which is insufficient for modeling natural phenomena. The time-fractional operators substantially draw some fantastic results in the fractal topics field for modelings with memory. Here, we are interested in representing some medical and physical studies in [
4,
5,
6,
7]. In particular, see the usefulness of Hilfer fractional operators in papers on some different diseases [
8,
9,
10].
The importance of controlled systems has arisen from Zadeh’s work [
11] with fuzzy sets used to understand the behavior of objects with a fractional grade of membership between zero and one. On the other hand, the controllability of fractional operators through the solvability region of mixed quasi-hemivariational inequalities has attracted attention to investigating and updating more results (in particular, with fuzzy sets). Here, we refer to [
12,
13]. In 2021, N. V. Hung [
14] gave us strong and more worthwhile results on the generalization of Levitin–Polyak well-posedness for controlled systems of minty type–fuzzy mixed quasi-hemivariational inequalities (FMQHI). For more readings, it is worth looking into the engineering, mechanics, and economics literature as well, for example, [
15,
16,
17,
18,
19,
20].
Among the most robust theories that support stochastic modeling are differential inclusion theories and the continuous infinite delay ones. Many scientific teams have been conducting research on this topic in many different scientific fields. For examples, see [
21,
22].
Some researchers have presented several results by modeling with control, stochastic, delay, and memory systems. Many kinds are found in [
12,
23,
24] and the references therein.
Y. Jiang et al. [
13] prove the solvability theory of mild solution sets for multi-valued Caputo fractional differential initial problems with hemivariational inequality (HVI) with Clarke generalized directional derivatives.
where
A is the infinitesimal generator of a norm-continuous and uniformly bounded
semi-group
and
F is a multi-valued map.
X. Pang et al. [
25] presented the mild solution of Hilfer differential inclusion under the solvability constraints of variational–hemivariational inequality (VHVI).
where
A represents the infinitesimal generator of a norm-continuous and uniformly bounded
semi-group
and
F is a multi-valued map.
R is a history-dependent operator and for the order
,
defines the fractional order Riemann–Liouville integral.
N. T. V. Anh [
26] focussed on the solvability of optimal control Caputo-fractional problems with HVI, Clarke-type subdifferentials and nonlocal initial conditions
where
is an admissible control set of
and
A denotes the infinitesimal generator of a norm-continuous and uniformly bounded
semi-group
.
are single-valued maps and
represents the Clarke-type generalized subdifferential operator of
G.
B is a bounded linear operator.
The new work comes to define the area that produces the data of fractional order derivatives with orders between zero and one associated with the one of fuzzy sets with grades with the same property. We suggest the fractional differential inclusion concerned with the generalized conformable Hilfer fractional operator depending on
and
with
[
2,
27]. That will be under the effect of infinite continuous delay. The reason for choosing this derivative is apparent if we know its benefits in describing control and diffusive systems and its decent iterating behavior in the order data
. This fact was explored in [
27] as a conformable fractional derivative. This type has the ability as a measure to show different straight lines and planes drawing specific curves and surfaces. A. Has et al. [
28] have produced an excellent study on the physical and geometric implications of the conformable type of derivatives talking about the attainability of approximating the tangent, which is not available with the classical type. We can overcome this limitation through the use of substitutional tangents. In addition, conformable derivatives are definable even if the tangent plane is undefined. For a general vision, the conformable tangent aircraft is available for all points containing points with undefined derivatives. On the other hand, the Hilfer derivative was presented as a generalization of Hilfer–Hadamard, Hilfer–Katugampola, Caputo–Hadamard, Riemann–Liouville, Hadamard, Hilfer, Caputo, etc., into single-form derivatives that draw a massive field of natural applications. For more details, see [
3].
Furthermore, we consider the mild solution set of the suggested inclusion in the solvability region of FMQHI of minty type endowed with the Clarke-type generalized directional derivative.
The problem considered here will be helpful in modeling heterogeneous natural systems with memory.
2. Setting of the Problem
Let be the family of all fuzzy sets over a given Banach space E. Then,
- (i)
is called fuzzy mapping, for all .
- (ii)
is fuzzy set on and consequently denotes the membership function of in .
- (iii)
Define by the set , the cut set of M for all .
Let be two reflexive Banach spaces, be a nonempty closed subset, and be the space of all linear continuous functions. Let Z be the control reflexive Banach space and be the set of all admissible controls which is nonempty and closed. Let and be fuzzy mappings and be a given locally Lipschitz function. Let , satisfying
- (1)
,
- (2)
,
for all
and let
be a function satisfying
We want to study Hilfer fuzzy-type fractional differential inclusion defined by
where
and
,
denote the generalized Hilfer-type fractional derivative and integral, respectively, that their definitions are given later, in
Section 3.2.
denotes a generator of compact
semi-groups and
defines solutions collection of the minty type FMQHI-controlled system written as follows.
: Find
such that
where
denotes the generalized directional derivative of Clarke type for the function
j at the point
in the direction of
given by the relation
is a control function and
are defined, respectively, by
- a:
,
- b:
3. Preliminaries and Auxiliary Statements
The main results depend on five important concepts: Hilfer fractional operators, semi-groups, infinite delay, multi-valued operators, and FMQHI. So, we must present some basic definitions and facts related to these concepts.
3.1. FMQH Inequalities
From [
14], we can see the following
Lemma 1. Let and . Then,is a nonempty set. Proof. Since
, then
and
. Taking
implies that
. Since
if
, then
. While
is nonempty and
exists and satisfies (
4), then
is a nonempty set. □
Definition 1. Let be the solution set of FMQHI. If
- (i)
is nonempty,
- (ii)
every LP approximating sequence for FMQHI has a subsequence which converges to some points of ,
then we say that FMQHI is LP well posed in the generalized sense.
Let us define the approximate solution set of FMQHI by
for arbitrary positive real numbers
.
We can see clearly that and
The following Lemma has been proved in [
29].
Lemma 2. Consider that both Banach spaces are reflexive. Let be a nonempty closed subset andDefine the control–reflexive Banach space by Z and assume the nonempty closed subset to be the collection of admissible controls. Suppose two fuzzy mappings and and a locally Lipschitz function j. Let both functions and be given. If - (i)
S is topologically closed on K and is l.s.c set-valued mapping with nonempty compact values on K;
- (ii)
P is l.s.c;
- (iii)
j is a locally Lipschitz function and f is u.s.c;
- (iv)
is u.s.c.
then, is a compact set for all . Furthermore, is u.s.c at 0 and for all , is compact.
Let both be set-valued mappings defined, respectively, as follows
- (i)
formed by
- (ii)
formed by
Consequently, we have the following Lemma
Lemma 3. Consider that both Banach spaces are reflexive. Let be a nonempty closed subset andDefine the control reflexive Banach space by Z and assume the nonempty closed subset to be the collection of admissible controls. Suppose two fuzzy mappings and and a locally Lipschitz function j. Let both functions and be given. Suppose the following conditions - (i)
is a compact continuous set-valued mapping defined by (5); - (ii)
is an l.s.c set-valued mapping defined by (6); - (iii)
j and f are, respectively, locally Lipschitz and u.s.c functions;
- (iv)
is u.s.c for each .
Then, the sufficient and necessary condition for FMQHI to be LP well-posed in the generalized sense is that is a nonempty set.
Definition 2. For FMQHI-controlled systems, we say that is a gap function if
- (i)
;
- (ii)
The two sentences and are equivalent.
Lemma 4. Suppose that and have compact values in a neighborhood of the reference point. The function , where defined byis a gap function for FMQHI-controlled systems. Moreover, the sentences and are equivalent. Lemma 5. For FMQHI, g is continuous in K if
- (i)
and are compact continuous set-valued maps;
- (ii)
f is continuous;
- (iii)
J is a locally Lipschitz function;
- (iv)
h is continuous, .
Lemma 6. Assume that is a real-valued function satisfyingWe can find a function ϕ satisfying (8) and (9) for whichif is LP well-posed in the generalized sense. 3.2. Fractional Calculus
Definition 3 (
Conformable Integrable Function)
. Let and with . Let where . Then, the operator given byrepresents a conformable fractional integral. Definition 4 (
Generalized Conformable (GC) Integrable Function)
. For an order , the left-side GC fractional integral with and is defined byfor all conformable type integrable functions x on the interval . Definition 5 (
Generalized Hilfer-type (GH) fractional derivative)
. Let and such that . For a conformable integrable function x on the interval , the left-side GH fractional derivative operator of order β and type θ is defined by Lemma 7. Let , and x all be defined as in Definition 5. Then, we have the following statements
- (1)
- (2)
for , - (3)
for ,where
Proof. In [
1]: Lemma 2 and Theorems 5 and 7, take
. Then, we obtain the statements above. □
For more details, see [
1,
2,
3,
27,
30].
3.3. Banach and Phase Banach Spaces
Here, we give some properties of Banach and phase spaces that help explore the solvability of the inclusion problem (
1)–(
3) with infinite delay.
3.3.1. Processes on Banach Spaces
According to both articles [
31,
32], the space
is a Banach space introduced with the norm
and
is endowed with the norm
Accordingly, we have the next theorem
Theorem 1 ([
31])
. Consider such that , then - (i)
Holder Inequality. If and . Then, and - (ii)
Minkowski Inequality. If . Then, and - (iii)
Embedding Theorem. If Ω
has a finite positive measure and . Then, and - (iv)
Definition 6. Let be given Banach spaces. Then,
- (a)
Compatible couple of Banach Spaces consists of two Banach spaces continuously embedded in the same Housdroff topological vector space V. The spaces and are both Banach spaces equipped, respectively, with norms
- (b)
Interpolation is the family of all intermediate spaces W between in the sense thatwhere the two included maps are continuous.
Remark 1. We can understand that:
3.3.2. Phase Banach Space
From [
33], denote by
the space of all continuous function mapping
to
. For
, let
be defined in
and continuous on
For all
, define
by
. Note that
translates
x from
back to
and
.
Definition 7. The set is said to be admissible whenever there exist two constants and a continuous function such that if is defined in and continuous on with , then for all the following statements all hold:
;
is continuous in t with respect to ;
;
for all .
Remark 2. In () let be given. We can see for all , and that , which implies the following: 3.4. Multi-Valued Mappings
Here, we introduce some facts about multi-valued mappings and their properties. These facts are confirmed in [
34,
35,
36,
37,
38].
Consider that we have two Banach spaces and . We say that is convex (closed) multi-valued mapping if is convex (closed) for all . If is relatively compact for every , then is completely continuous.
is said to be upper semi-continuous if is a closed subset of W for each closed subset (i.e., the set is open whenever is open). In contrast, it is lower semi-continuous if is an open subset of W. By another meaning, is lower semi-continuous whenever the set is open for all open sets .
We say that a multi-valued map is measurable if for every the function is an measurable function.
Given
, the Pompeiu–Housdorff distance of
is defined by
Moreover, the diameter distance of
V is given by
Note that there exists
such that
if
V is bounded.
Suppose we adopt as a nonempty compact valued completely continuous function. In that case, [ is upper semi-continuous] is equivalent to [ has a closed graph (i.e., if , then implies )].
Definition 8. Consider a multi-valued map . Then, Θ is said to be a Caratheodory if
- (1)
is measurable, .
- (2)
a.e is upper semi-continuous.
Adding to the assumptions (1) and (2), the map Θ is - Caratheodory if for each there exists satisfying and and a nondecreasing map Ł for whichfor all . Lemma 8 ([
39] (pp. 781–786))
. Let Ω be a Banach space,be a Caratheodory multi-valued map and P be a continuous and linear map from to . Then, the operator:such that:is an operator with closed graph in . Theorem 2 (
Leray–Schauder Nonlinear Alternative Type [
40] (p. 169), [
41] (p. 188))
. Assuming that Σ is Banach space, E is a convex closed subset of Σ, and Ω is an open subset of E with . If is an upper semi-continuous multi-compact map, then either - (i)
there exists such that , or
- (ii)
there exists a fixed point .
3.5. Auxiliary Statements
Lemma 9. Take the function for which we haveThen, the unique conformable solution is given bywhereand Proof. By applying
to both sides of (
11) and applying condition (
12), one has
Take
So, we obtain
The proof is similar to the proof of the solution in [
30]: Theorem 4.
Now, to obtain the conformable solution, define the operator
ℑ by
Accordingly, define the sequence
by
Hence, we obtain the general formula
Take the limit as
and apply the changing
; we have
□
Now, define the set-valued map
such as
and define the linear operator
for all
by
After that, define the operator
by
where
and then define the operator
such as
Proposition 1. Let be given and define , respectively, by , and . Then, the following statement is satisfied Now, since is a generator of compact semi-groups, there exists such that and consequently we have the following proposition.
Proposition 2. Let be given and define , respectively, by and . Then, the following statement is valid. Proof. Using [Lemma 7: (1)], one has
□
Define the statement
: For some
we have
where
Then, define the set
K by
It is clear that
K is closed in
and in the phase Banach space
.
Consider the following hypotheses.
The mappings and f satisfy all conditions given in Lemmas 2 and 3;
is Caratheodory multi-valued mapping satisfying the below condition;
For each
there exist
and non-decreasing functions
such that
for all
and
is compact;
The mappings and f satisfy all conditions given in Lemmas 2, 4 and 5;
is Caratheodory multi-valued mapping satisfying the below condition.
For each
, there exist
and non-decreasing functions
and
such that
for all
and
is compact, where
is defined by (
8)–(
10) in Lemma 6 with
and
Then, for all we have the following propositions
Proposition 3. Let be given. The operator is convex if holds.
Proof. Let
; then, there exist
subject to
where
is defined by (
14)–(
16). Let
be given. Then, by the linearty of
, we obtain
By
and then
which completes the result. □
Proposition 4. Let with be given. The operator is completely continuous if and are fulfilled and so are –.
Proof. To show that is equicontinuous, we should prove that is bounded and relatively compact on bounded subsets.
Step 1: Let
and
; then,
By using Propositions 1 and 2 and Lemma 7:(1) we have
where
and
Step 2: Suppose that
such that
with
and take
where
It is easy to understand that as since is strongly continuous in .
For
, we have
Hence,
as
Since
is also strongly continuous in
and
then we can see that
as
.
Finally,
which shows that
as
.
Because of that, and as , then we obtain the result as .
According to Steps 1 and 2, we conclude that is completely continuous. □
Proposition 5. Let with be given. The operator is upper semi-continuous if and – are satisfied.
Proof. Since is completely continuous, it is enough to claim that it has a closed graph to obtain the upper semi-continuity of . Let and . If , there exists such that . Using the linearity of and Lemma 8 shows that has a closed graph. Thus, . Take , then we obtain which tends to the upper semi-continuity of . □
4. Main Results
Theorem 3. Consider that hypothesis and – are valid. Then, problem (1)–(3) has at least one solution in K if the following condition holdswhere Proof. To obtain the suggested result, we follow all arguments given in Lemma 8 and Theorem 2 for the operator over the closed convex subset K.
Step 1: Let
and
. We want to claim that
. So, since
implies the existence of two elements,
such that
where
is defined by (
14)–(
17). Due to the linearty of
, we can see the linearty of
and by using Proposition 3 and the convexity of
, we have
We can understand the proof since
is convex due to Proposition 3.
Step 2: To show that that is completely continuous in K, we need to prove that and is equicontinuous.
Let
. By using Proposition 4 Step 1, one has
Let with
- Case 1:
If
, then by continuity of
in
we obtain
- Case 2:
If
, then by using Proposition 4 Step 2, one has
- Case 3:
If
and
, then there exists
such that
which implies that
. According to Case 1 and Case 2, we have
as
By and , we conclude that ℵ is completely continuous in K.
Step 3: We still need to explore that ℵ has a closed graph to see the upper semi-continuity of ℵ. In the vision of Proposition 5 and the continuity of , we understand the upper semi-continuity of ℵ.
Step 4: For the set
K, we choose
By Theorem 2 and Step 1–Step 4, we conclude the solvability of problem (
1)–(
3). □
Theorem 4. Consider that hypotheses – and – are satisfied. Then, problem (1)–(3) has at least one solution in K if the following condition is valid.where ,and . Proof. Similarly to the proof of Theorem 3, we take
□