A Time-Symmetric Resolution of the Einstein’s Boxes Paradox
Abstract
:1. Introduction
2. The Einstein’s Boxes Paradox
Suppose a particle is enclosed in a box B with impermeable walls. The associated wave is confined to the box and cannot leave it. The usual interpretation asserts that the particle is “potentially” present in the whole of the box B, with a probability at each point. Let us suppose that by some process or other, for example, by inserting a partition into the box, the box B is divided into two separate parts and and that and are then transported to two very distant places, for example to Paris and Tokyo. The particle, which has not yet appeared, thus remains potentially present in the assembly of the two boxes and its wavefunction consists of two parts, one of which, , is located in and the other, , in . The wavefunction is thus of the form , where .
The probability laws of [the Copenhagen Formulation] now tell us that if an experiment is carried out in box in Paris, which will enable the presence of the particle to be revealed in this box, the probability of this experiment giving a positive result is , while the probability of it giving a negative result is . According to the usual interpretation, this would have the following significance: because the particle is present in the assembly of the two boxes prior to the observable localization, it would be immediately localized in box in the case of a positive result in Paris. This does not seem to me to be acceptable. The only reasonable interpretation appears to me to be that prior to the observable localization in , we know that the particle was in one of the two boxes and , but we do not know in which one, and the probabilities considered in the usual wave mechanics are the consequence of this partial ignorance. If we show that the particle is in box , it implies simply that it was already there prior to localization. Thus, we now return to the clear classical concept of probability, which springs from our partial ignorance of the true situation. But, if this point of view is accepted, the description of the particle given by , though leading to a perfectly exact description of probabilities, does not give us a complete description of the physical reality, because the particle must have been localized prior to the observation which revealed it, and the wavefunction gives no information about this.
We might note here how the usual interpretation leads to a paradox in the case of experiments with a negative result. Suppose that the particle is charged, and that in the box in Tokyo a device has been installed which enables the whole of the charged particle located in the box to be drained off and in so doing to establish an observable localization. Now, if nothing is observed, this negative result will signify that the particle is not in box and it is thus in box in Paris. But this can reasonably signify only one thing: the particle was already in Paris in box prior to the drainage experiment made in Tokyo in box . Every other interpretation is absurd. How can we imagine that the simple fact of having observed nothing in Tokyo has been able to promote the localization of the particle at a distance of many thousands of miles away?
3. The Conventional Formulation of Einstein’s Boxes
4. The Time-Symmetric Formulation of Einstein’s Boxes
5. Discussion
Funding
Institutional Review Board Statement
Informed Consent Statement
Data Availability Statement
Acknowledgments
Conflicts of Interest
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Heaney, M.B. A Time-Symmetric Resolution of the Einstein’s Boxes Paradox. Symmetry 2022, 14, 1217. https://doi.org/10.3390/sym14061217
Heaney MB. A Time-Symmetric Resolution of the Einstein’s Boxes Paradox. Symmetry. 2022; 14(6):1217. https://doi.org/10.3390/sym14061217
Chicago/Turabian StyleHeaney, Michael B. 2022. "A Time-Symmetric Resolution of the Einstein’s Boxes Paradox" Symmetry 14, no. 6: 1217. https://doi.org/10.3390/sym14061217
APA StyleHeaney, M. B. (2022). A Time-Symmetric Resolution of the Einstein’s Boxes Paradox. Symmetry, 14(6), 1217. https://doi.org/10.3390/sym14061217