1. Introduction
The paper is a continuation of the paper by the authors [
1], where to obtain the asymptotics of the solution of the Cauchy problem (
1) and (
2), the positive Hill operator (
) and the properties of the spectrum
of this operator were studied.
Here, we will consider the case when the Hill operator is non-positive (), which means that the left end of the spectrum of the Hill operator on the complex plane of the variable coincides with zero or negative.
This paper also studies the behavior of the solution for
and
of the following Cauchy:
where the functions
and
are periodic with period 1,
We also assume that the functions and are continuous or have a finite number of discontinuities of the first kind on the period, , ; b is an arbitrary fixed constant.
For the completeness of the description of these problems, we note that the study of the behavior as
as a solution of the problems (
1) and (
2), and the corresponding multidimensional problems, provided that the potential differs from a constant by a finite function or is sufficient, rapidly tends to a constant at infinity; many papers and books are devoted to this area (see, for ex. [
1,
2,
3,
4,
5,
6,
7,
8,
9]).
Let us point out some papers in which the problems are studied, similarly to the problems (
1) and (
2), with different conditions on the potential and coefficients.
The behavior at large time
t of the solution of the Cauchy problem for the hyperbolic equation
was studied in [
3,
4]. In [
4], under the assumption that the function
tends in a certain way to the limit as
, some estimates for the rate of decay of the solution as
, related to the stabilization rate
at
were obtained; that is, the estimates
and
are satisfied for some
as
.
Paper [
5] studies that a perturbed Hill operator with an exponentially decreasing impurity potential has a resonance (or an odd number of resonances) at each sufficiently distant lacuna on the second (“non-physical”) sheet.
In [
6], for the one-dimensional perturbed Hill operator
H, whose impurity potential has a finite first moment, the “Levinson series” is obtained. This series of relations generalize the well-known Levinson formula to the case when there is a periodic potential. The “Levinson series” is an effective tool for studying the discrete spectrum in lacunae (gap bands). In particular, it is shown that in the case of a reflectionless impurity potential with a finite second moment, there are no eigenvalues of the operator
H in the distant lacunae of the spectrum.
In [
7], for the Hill operator with a 1-periodic potential
with the condition
, estimates of the periodic potentials are established for gap lengths.
We also note paper [
8], in which the one-dimensional stationary Schrödinger equation with a quasi-periodic potential
is studied. It is shown that if the frequency vector
is large enough, the Schrödinger equation admits two linear independent Floquet solutions for a set of positive energy measure.
Note that in [
9], the behavior of the solution of the Cauchy problem for a hyperbolic equation with a periodic potential
is also studied, that is, a problem similar to the problems (
1) and (
2), which are considered in this paper with
.
In the case of periodic coefficients
and
, the first results on the behavior of solutions of the Cauchy problem and the initial-boundary value problem of both homogeneous and inhomogeneous hyperbolic equations were obtained in [
10,
11].
In addition to the papers and books mentioned above, we also note more important literature, such as [
12,
13,
14,
15,
16], which reflect the spectral properties of the Hill operator from different points of view. In particular, the papers [
12,
13] were also devoted to the definition of the Hill equation from its spectrum.
Let us present a scheme for studying the Cauchy problem (
1) and (
2), for the case of a non-positive Hill operator. To solve the Cauchy problem (
1) and (
2), in the case when the left end of the spectrum of the Hill operator coincides with zero or is negative, it is necessary to make a Fourier transform to reduce the Cauchy problem to a stationary problem. Then, we write the solution of this problem in terms of the resolvent of the Hill operator and apply the inverse Fourier transform. When the left end of the spectrum coincides with zero, at the point
, the vertical cut in the lower half-plane of the variable
k is not made. At the negative left end of the spectrum, the approach to solving the problem is the same as in [
1].
Notations: is the space of measurable functions in
for which
The Sobolev space
in
is defined as:
provided with the norm
2. Preliminaries
Definition 1. A function is called a periodic (anti-periodic) solution of the Cauchy problems (
1)
and (
2)
if it satisfies the relationfor any and , with and in the case of periodic and anti-periodic solutions, respectively. 2.1. Spectrum and Green’s Function of the Hill Operator
Continuing the function
by zero in the region
, and applying the Fourier transform with respect to the variable
t in the Cauchy problem (
1) and (
2), for the function
we obtain the equation
For any function
from
, we define its norm in the same space
If the function is defined on the entire axis , then by , we denote the restriction of this function on the segment .
Let us present some necessary facts from the spectral theory of differential equations. For any function , we denote by the derivative with respect to x and by the derivative with respect to k
Let
be the fundamental system of solutions of the homogeneous (for
) Equation (
3) such that
It is known [
17] that
and
are entire functions in
k real on the real axis, and for
, we have the form
uniformly in
. These expansions can be differentiated with respect to
x and with respect to
k.
Let us denote and . The functions and are even on the real axis of the complex plane of the variable k.
The Hill operator is the differential operator
generated in the Hilbert space
by the operation
where the functions
and
are periodic with period 1.
The spectrum of the Hill operator is absolutely continuous and is a finite or infinite sequence of isolated segments (zones) separated by lacunae going to infinity.
Note that the Hill operator has only a continuous spectrum, which lies on the real axis and is left semi-bounded [
17]. Let us replace the spectral parameter
by
so that the spectrum
of the operator
on the complex plane of the variable
k consists of points for which
does not have a bounded inverse on an everywhere dense set in
.
For a more detailed characterization of the spectrum of the Hill operator , consider the following periodic (anti-periodic) Sturm–Liouville problems.
Let
be an eigenfunction of the periodic Sturm–Liouville problem:
and
is the eigenfunction of the anti-periodic Sturm–Liouville problem:
normalized by the condition
, where
and
,
, is the set of all eigenvalues of problems (
5) and (
6), respectively, numbered in ascending order, taking into account the multiplicity.
Continuing the function (or ) to the entire real axis, in a periodic (or anti-periodic) way, we obtain a function, which we denote by (or ).
Since Equation (
3) contains the parameter
, by replacing the spectral parameter
by
, we can use the expression “complex plane of the variable
k” instead of the expression “complex plane of the variable
”.
Denote by
the complex plane, as in [
1], in which vertical cuts were made from the points
in the lower half-plane of the variable
k.
In this article, the complex plane will be defined separately, depending on the cases and .
2.2. Auxiliary Statements
For the convenience of reading this article, we present the formulations of some Propositions and Lemmas from [
1].
Proposition 1 ([
1]).
For the solution of the problems (
1)
and (
2)
, the following representation is valid:where the function for and satisfies the estimate Proposition 2 ([
1]).
For any and , we have the estimate As is known [
17], if
and
are the ends of a lacuna, then
is a simple eigenvalue of the periodic Sturm–Liouville problem (
5), and
is a simple eigenvalue of the anti-periodic Sturm–Liouville problem (
6).
For the eigenfunction of problem (
5), corresponding to the eigenvalue
, we will search in the form
Therefore, we obtain the following system
Since
are simple eigenvalues of problem (
5), then the determinant of the system (
7) is equal to zero, and all coefficients of the system do not vanish simultaneously. Together with the equality
for
(this results from the fact that
), which served as the definition of the numbers
, this leads to the fact that at the points,
satisfies one of the following relations:
Note that for any , the functions and are even on the real axis of the complex plane of variable k.
Lemma 1 ([
1]).
For points , if are the ends of lacunae (that is, simple zeros of the function ), then the equalitiesare satisfied, where the function is the eigenfunction of the periodic Sturm–Liouville problem, and the numbers depending on the cases – have the form 3. Main Results
3.1. The Case When the Left End of the Spectrum of the Hill Operator Coincides with zero:
If on the complex plane of the variable
, the left end of the spectrum
of the Hill operator
coincides with zero, then on the complex plane of the variable
k, the spectrum
of the Hill operator
is merging segments:
The point is a two-fold zero of the function , and this means that the simple zero of the function .
Denote by
and
L the complex plane and contour, as in [
1], for which vertical cuts were made from the points
in the lower half-plane of the variable
k. In this case, no vertical cut is drawn from the point
.
On the complex plane
, we consider the contour
L, which can be represented as
where
and
are defined in the same way as in [
1],
.
For the integrals
and
, which are defined in [
1], estimates (17) and (18) remain valid. The function
for
and
at the point
can have a first-order pole, since
is a simple zero of the function
.
Let
be some finite contour in
. Denote by
the integral
Proposition 3. For the solution of problems (
1)
and (
2)
, the following representation iswhere the function for and satisfies the estimate:and the function has the form Proof. The proof of this statement is similar to the proof of Proposition 1 from [
1]. Due to the fact that in this case, no vertical cut is made from the point
into the lower half-plane of the variable
k, the term
is separated in the expansion of the solution of the Cauchy problem (
1) and (
2). Furthermore, this term is also separated in the asymptotic representation of the periodic solution of the Cauchy problem. □
Theorem 1. If the left end of the spectrum of the Hill operator on the complex plane of the variable λ coincides with zero, , then the solution of the Cauchy problem (
1)
and (
2)
for and has the formwhere is a periodic solution of the Cauchy problem, for which is a anti-periodic solution of the Cauchy problem, for whichthe function is defined aswhile the function for and satisfies the estimate The function
is obtained from the normalized eigenfunction
of the periodic Sturm–Liouville problem (
5) corresponding to the eigenvalue
, if it is continued along the entire axis in a periodic way,
is some constant defined by the formula (
10) below.
Here, the summation is carried out only over those n for which (or ) are simple eigenvalues of the periodic (or anti-periodic) Sturm–Liouville problem.
Proof. Denote by the circle and .
Since the function
has a simple zero at the point
, and in a small neighborhood,
of this point has no other zeros, then for
, the following equality holds:
and
Taking into account the formula (
8), we obtain
By Lemma 1 from [
1] for
Proposition 3 together with the Formulas (
9) and (
10) implies the validity of the theorem. □
3.2. The Case When the Left End of the Spectrum of the Hill Operator Is Negative
Let us now consider the case when the left end of the spectrum of the Hill operator is negative on the complex plane of the variable and coincides with the point ().
It is known [
17] that
is the smallest and simple eigenvalue of the Sturm–Liouville problem (
5).
If the left end of the spectrum
of the Hill operator
coincides with the point (
), then a part of the spectrum of the Hill operator
on the complex plane of the variable
k is located on the imaginary axis. Then, the highest point of the spectrum on the imaginary axis will be
. At the point
, the function
has a branch point, since the point
is a simple zero of the function
[
17].
Let us cut the complex plane of the variable k along the vertical ray and denote the resulting domain by .
Let us put
where the branch of the root is determined by the condition
for
.
Note that the function
has branching only at the ends of the lacuna [
17], so
and
are single-valued in
. Then, for any
We define Green’s function of Equation (
3) for
k from the upper half-plane
and, taking into account the identities (
11) and the equality
we obtain
where
The solution to problems (
1) and (
2) has the form
where
a is some positive constant.
Note that Green’s function for every continues analytically to .
To study the properties of the (
13) integral, we introduce the following notation:
,
, and
is the segment
,
l is any real number.
From the relations (
4), it follows that
moreover,
can tend to infinity in any way, so in (
14), one can replace the line
by
. In addition, according to (
4), we have
where
is an entire function
for each
, and the function
for
uniformly in
has the form
Let us explore these integrals. Putting
with
, we obtain
where
Let us examine the first term in (
16). Consider the function
For any fixed
, we have
and
where
does not depend on
f and
x.
For all
, due to the Parseval equality for the Fourier transform, we have
The second term of the equality (
16) is studied in a similar way. Therefore, for any fixed
,
where
does not depend on
f and
x.
In article [
18], an elegant method is presented that allows, in the case of a periodic potential
, to obtain a very simple Parseval formula for the problem in the entire space.
By the Cauchy–Schwartz inequality and the last inequality, from (
15), we obtain
where
depends only on
b.
In the same way, we obtain
where
depends only on
b.
To investigate
, we note that
By the Cauchy–Schwartz inequality, we obtain the estimate
where
depends only on
b.
From the estimates for
,
, and
, it follows that
Likewise, for the integral
we obtain the estimate
Thus, we learn that the integrals and decrease exponentially as .
Let us choose the number in two ways:
- (i)
, if on the imaginary axis, except for the point , there are no other branch points of the function ;
- (ii)
, where is the distance from the point to the nearest branch point of the function located on the imaginary axis.
Denote by the contour going from the point along the left edge of this cut to the point , and then from the point along to the right edge of the cut up to the point .
Green’s function is defined by formula (
12), where the single-valued branch of the root
is determined by the condition
.
Let .
Proposition 4. For the solution of the problems (
1)
and (
2)
, the following representation is valid:where the function for and satisfies the estimate Proof. This statement is proved similarly to the proof of Proposition 1 from [
1], where
is considered instead of
from [
1], and
with
. □
Proposition 5. For any and we have the estimate Proof. The proof of this statement is similar to the proof of Proposition 2 from [
1], where
is considered instead of
from [
1], and
with
. □
Theorem 2. If the left end of the spectrum of the Hill operator is negative on the complex plane of the variable λ and coincides with the point , then the solution of the Cauchy problems (
1)
and (
2)
for and has the formwherewhile the function for and satisfies the estimate The function
is obtained from the normalized eigenfunction
of the periodic Sturm–Liouville problem (
5) corresponding to the eigenvalue
, if it is continued along the entire axis in a periodic way.
Proof. To complete the proof of the theorem, by virtue of Propositions 2 and 3, it remains to study the following integral:
Let
. It is easy to show that for
, the following representation holds:
and the branch of the root
is selected from the condition of its positivity for positive values of
.
For
we set
, where
. It is easy to see that if
k belongs to the left side of the contour
, then the following equality holds
and if
k belongs to the right side of the contour
, then the root has the opposite sign. The values of the function
coincide at the corresponding points of the left and right parts of the contour
.
Considering that
is on the left side of the contour, and
on the right side of the contour, we learn that
Making the change of variables
into the integral (
17), we obtain
To study the inner integral in (
18), we use Watson’s lemma [
19], then
Now, substituting (
19) into (
18), we obtain
Arguing in the same way as in the proof of Lemma 1 from [
1], we can show that
where the constant
is determined depending on which of the conditions
is satisfied at the point
.
From (
20) and (
21), it follows
From Propositions 2 and 3, as well as from (
22), the validity of Theorem 2 follows. □