1. Introduction
It is well known that the Riemann zeta-function
shows analytic continuation to the whole complex plane, except for a simple pole at the point
, and satisfies functional equation
where
denotes the Euler gamma-function. The majority of other zeta-functions also have similar equations, which are referred to as the Riemann type. Epstein in [
1] raised a question to find the most general zeta-function with a functional equation of the Riemann type and introduced the following zeta-function. Let
Q be a positive defined quadratic
matrix, and
for
. Epstein defined, for
, the function
continued analytically it to the whole complex plane, except for a simple pole at the point
with residue
, and proved the functional equation
In [
2], Bohr and Jessen proved a probabilistic limit theorem for the function
. We recall its modern version. Denote by
the Borel
-field of the topological space
, and by meas
A the Lebesgue measure of a measurable set
. Then, on
, there exists a probability measure
such that, for
,
converges weakly to
as
(see, for example, [
3] (Theorem 1.1, p. 149). In [
4], the latter limit theorem was generalized for the Epstein zeta-function
with even
and integers
. Namely, on
, there exists an explicitly given probability measure
such that, for
,
converges weakly to
as
.
For the function
, more general limit theorems are also considered. In place of (
1), the weak convergence for
with certain measurable function
is studied. For example, theorems of such a kind follow from limit theorems in the space of analytic functions proved in [
5].
Suppose that the function
is defined for
, is increasing to
, and has a monotonic derivative
satisfying the estimate
Denote the class of the above functions by
.
The aim of this paper is to prove a limit theorem for
when
. In place of
one can consider
It is easily seen that the weak convergence of
to
as
is equivalent to that of
. Actually, if
converges weakly to
as
, then
for every continuity set
A of the measure
. Since
we obtain that
i.e.,
converges weakly to
as
.
Now, suppose that (
2) is true. Then
where
as
. Taking
and summing the above equality over
, we obtain, ue of
-additivity of the Lebesgue measure,
Let
. We fix
such that
Then
Thus, taking
and then
, we find
This together with (
3) shows that
i.e.,
converges weakly to
as
.
Since, in the case of the function occurs for large values of t, the study of sometimes is more convenient than that of . Therefore, we will prove a limit theorem for .
As in [
3], we use the decomposition [
6]
where
and
are zeta-functions of certain Eisenstein series and of a certain cusp form, respectively. The latter decomposition and the results of [
7,
8]—see also [
9]—imply that, for
,
where
,
,
and
are Dirichlet
L-functions, and the series is absolutely convergent for
. Equality (
4) is the main relation for investigation of the function
. Before the statement of a limit theorem, we construct a
-valued random element connected to
.
Let
is the set of all prime numbers,
, and
where
for all
. The infinite-dimensional torus
is a compact topological Abelian group; therefore, the probability Haar measure can be defined on
. This gives the probability space
. Denote by
the
pth,
, component of an element
, and extend the function
to the whole set
by the formula
On the probability space
, for
, define the
-valued random element by
where
and
Now, denote by
the distribution of
, i.e.,
Because
,
for
. Therefore, the second Euler product for Dirichlet
L-function is convergent for almost all
and defines a random variable.
The main the result of the paper is the following theorem.
Theorem 1. Suppose that , and is fixed. Then converges weakly to the measure as .
Since the representation (
4) depends on
Q, the random element
depends on
Q. Thus, the limit measure
also depends on
Q.
3. Limit Theorems
We divide the proof of Theorem 1 into lemmas that are limit theorems in some spaces.
We start with a lemma on the torus
. For
, define
Lemma 3. Suppose that . Then converges weakly to the Haar measure as .
Proof. We will apply the Fourier transform method. Let
,
be the Fourier transform of
, i.e.,
where “*” indicates that only a finite number of integers
are distinct from zero. Thus, by the definition of
,
Obviously,
Now, suppose that
. Since the set
is linearly independent over the field of rational numbers, we have
Then
where
. Since
,
as
. Therefore,
Similarly, we find that
Thus, (
10)–(
12) show that
Since the right-hand side of the latter equality is the Fourier transform of the Haar measure
, the lemma is proved. □
For
, define
To prove the weak convergence for
as
, consider the function
given by the formula
where
and
is the Dirichlet series for
. Clearly, the above series are absolutely convergent for
. The absolute convergence of the series for
implies the continuity for the function
. Therefore, the function
is
-measurable, and we can define the probability measure
, where
Lemma 4. Suppose that and is fixed. Then, converges weakly to as .
Proof. By the definitions of
,
and
, for all
,
Thus,
. Therefore, the lemma is a consequence of Theorem 5.1 from [
10], continuity of
and Lemma 3. □
The measure is very important for the proof of Theorem 1. Since is independent of the function , the following limit relation is true.
Lemma 5. Suppose that is fixed. Then converges weakly to as .
Proof. In the proof of Theorem 2 from [
4], it is obtained (relation (
12)) that
converges weakly to a certain measure
, and, at the end of the proof, the measure
is identified by showing that
. □
For convenience, we recall Theorem 4.2 of [
10]. Denote by
the convergence in distribution.
Lemma 6. Suppose that the space is separable, and -valued random elements , are defined on the same probability space with measure P. Let, for every k,andIf, for every ,then X. Proof of Theorem 1. Suppose that
is a random variable defined on a certain probability space
and distributed uniformly in
. Since the function
is continuous, it is thus measurable, and
is a random variable as well. Denote by
the complex valued random element having the distribution
, and, on the probability space
, define the random element
Then, in view of Lemma 4,
and, by Lemma 5,
Define one more complex-valued random element
Then, an application of Lemma 2 gives, for
,
This, relations (
13) and (
14) show that all hypotheses of Lemma 6 are satisfied. Therefore,
and this is equivalent to the assertion of the theorem. □