3.1. Diagrams for Semi-Canonical Words
So, we are working with a presentation of a group: , where A is a (finite) set of generators and is a set of relations, which we will assume to be closed under taking inverses and cyclic shifts.
Our ultimate goal is to construct a canonical form for each word in G that would simplify the process of analyzing Van Kampen diagrams for the group. As a first step towards this goal, we introduce the concept of -diagrams.
Let us fix a constant (it is productive to think of as a sufficiently small number). Also, for each relation , we define the relative length of each subword S in R as .
Definition 2. For a word W in the alphabet , we call an -diagram of W the collection of all subwords S (we distinguish the occurrence of the same subword at different positions in W) such that and , where , , , and the relative length . We call a diagram maximal if it contains only maximal subwords S in terms of inclusion.
This definition may seem somewhat convoluted, but in reality, it is quite natural. For a word W, we are interested in the potential possibilities for its cancellations, and each such possibility corresponds to a piece of relation from that occurs in our word. Moreover, even a repeated occurrence of a relation is considered as a potential cancellation opportunity. Finally, if we do not limit the length of the subwords of interest from below, we would include too many uninteresting words in the -diagram—for example, every symbol occurring in any relation. To avoid this, we only consider subwords of relations with a relative length of at least .
We assume that our group satisfies the conditions of small cancellation with a constant (this assumption will be implied everywhere until the consideration of graded systems of relations begins). In our terms, this means that if , , then , . Moreover, we require the inequality . This condition gives us an important restriction on the possible structure of maximal -diagrams:
Lemma 2. Under these conditions, in the maximal -diagram of a word W, no letter is included in 3 or more subwords S simultaneously.
Proof. Let
be subwords in the maximal diagram, let
and
be their respective relations, and let
P be the area of their intersection:
,
. In this case, the relative length
,
. Let some third subword
Q intersect
P. From maximality,
Q cannot be contained in
. Thus, it must extend beyond the boundaries of
either to the left (
Figure 4, left) or to the right (
Figure 4, right).
The first case is impossible, as the relative length of Q is at least , and either or would have a relative length greater than . The second case is impossible, as then Q would cover , but . Thus, the intersection of three maximal subwords at one point is impossible. □
At this point, we have introduced the constants
and
, which are useful to think of as numbers close to zero. For further reasoning, we will also need the constants
and
, subject to the following conditions:
The technical details that make these conditions necessary will become clear later. Thus, it is useful to think of
as large numbers that are nevertheless distinct from 1 and
(see
Figure 5). With these constants introduced, we can finally give the main definition of this subsection:
Definition 3. A word W is called λ-semicanonical (denoted ) if for every subword S (and relation R whose subword is S) in the maximal -diagram of W, we have .
Thus, we are interested in words where all occurrences of defining relations are sufficiently small. It is natural to study such words because if a word contains a large portion of a relation, it can be effectively canceled. The remainder of this subsection will be devoted to establishing the main properties of semicanonical words, constructing a group structure on them, and proving the equivalence between the obtained group and the original group G.
It is evident that the primary tool for manipulating words in
G is finding a subword
S such that there exists a relation of the form
and replacing
S with the subword
. We refer to each such replacement as an
-turn. The schematic representation we will use to depict this transformation is shown in
Figure 6. The black line corresponds to the original word, and the green line represents the resulting word.
Furthermore, different -semicanonical words can actually be equivalent in group G. To address this issue, we introduce the following:
Definition 4. Two words and in are called equivalent if there exists a sequence of -turns transforming the word into the word such that all intermediate words belong to .
Note that although this is indeed an equivalence relation (transitivity, reflexivity, and symmetry are evident from the construction), it is initially not obvious why such a definition (specifically, the requirement on
-semicanonicity of intermediate words) is natural and reasonable. Nevertheless, everything becomes much clearer after considering the following diagram in
Figure 7:
Here, the horizontal line denotes a sequence of characters in the word . The green and blue strips represent the elements and , respectively, of the maximal diagram. Suppose the first transformation we make is an -turn with respect to the first (green) subword. The second turn is with respect to the subword . The resulting word is indicated by the purple line. However, in this case, as can be seen from the diagram, after the first turn, the intersecting elements of the maximal diagram with can change because the intersection is no longer present in the word. In this particular case, decreases, but it is clear that some turns (e.g., the inverse of the given one) can increase the length of neighboring subwords in the diagram. However, since at each stage two distinct words intersect by at most , the length of each subword S in the diagram can change by no more than (due to the turns immediately to the right and left of S). Thus, by requiring a sufficiently large difference between and (at least ), we ensure that any sequence of turns on subwords that were initially part of the diagram does not create in the diagram subwords with a relative length greater than .
On the other hand, it is easy to see that each turn allowed by our definition is a turn using one of the subwords in the initial maximal diagram . Indeed, every turn replacing S with must satisfy (otherwise, the resulting word does not belong to ). However, the subwords of S consisting of subwords from other relations have a relative length of at most (see the proof of Lemma 2). Thus, S has a part with a size of at least that does not come from other relations, which means that S was included in the initial maximal -diagram.
Finally, the first condition on the constants () is necessary for each new subword to be included in the diagram again (otherwise, it may become too small and disappear from the diagram altogether, as we consider only segments of relations with a relative length of at least .
Combining Lemma 2 and Definition 4, we obtain the following lemma:
Lemma 3. In the conditions of Definition 4, the result of applying a sequence of turns to the subwords in the maximal -diagram W does not depend on the order of their application.
Proof. Note that the lemma statement is meaningful since the condition implies that all turns are indeed performed on some subwords in the initial diagram (possibly lengthened or shortened by due to previous turns). We proceed by induction on the number of turns. It is clear that it suffices to show that the new turn commutes with the last one made. If the subword used for the new turn is separated by at least symbols from the previous turn, commutativity is obvious. Otherwise, we have the situation depicted in diagram 7, and commutativity is evident from considering the diagram: applying turns 1 and 2 in any order leads to the word marked by the purple line. □
Establishing that the result does not depend on the order of turns but only on the subwords on which we perform these turns, and based on Lemma 2, which postulates that all subwords in the maximal diagram are arranged sequentially and intersect by no more than
, we can schematically depict each equivalence class of some
-canonical word in a more symmetric form. A typical example of such a depiction is shown in
Figure 8. Here, each cell of the graph corresponds to a relation from
and the corresponding subword in the maximal
-diagram
W (the reverse is also true: for each subword in the maximal
-diagram, we obtain the corresponding segment in the one-layer map). It is clear that the length of each horizontal segment does not exceed
, and the length of each vertical bridge does not exceed
.
Each word in the equivalence class W is represented as a path going from left to right in this diagram—choosing either the upper or lower segment for each segment. Each turn performed during the equivalent transformations of W is now represented as “switching” of the path from one alternative segment to another, and it is evident from this representation that the turns commute with respect to different subwords in the diagram. We call such a representation a one-layer map for the equivalence class of some -canonical word W. These maps will be the basis for all subsequent reasoning.
The next step is to construct a group structure on the set of equivalence classes in (i.e., on the set of one-layer maps). It is clear that we want to use the same map read in reverse as the inverse element in this group. However, if we define the multiplication of two maps as their immediate concatenation, the product of a map with its inverse will not be equal to the identity (the empty map). Therefore, a more elegant algorithmic definition of multiplication for two maps is introduced.
To multiply the map C by the map D, we start by comparing the maps and D symbol by symbol. We continue the comparison until we find the first place (either a symbol not participating in the -diagram or a cell in the map) where a difference occurs. Next, several possibilities arise:
The common part of and D is depicted in black, while the corresponding extensions are depicted in blue and green.
If the first variant is realized (the distinguishing point is a symbol not included in the -diagram), then the product of the maps is the concatenation of the blue and green parts. If the second variant is realized (the distinguishing point is a cell of the map, but the two possible extensions have disjointed subwords as bridges to this cell), then the product is obtained by concatenating the blue and green parts, with the insertion in the middle of one or both of the paths passing through the central cell depending on whether one or both of the lengths of these paths satisfy the condition . Finally, in the third case, only the “short” segment of the central cell will be included in the product since its relative length does not exceed , which means that the length of the alternative path is too large.
It can be seen that with this multiplication algorithm, the map read in reverse indeed becomes the inverse element. It remains to verify that the introduced multiplication operation is associative, which is quite obvious (it is sufficient to note that the disappearance of the “merged” ends of the diagram does not affect the central cell, and therefore, the tails can be deleted in any order).
Thus, we have introduced a group structure on the set of one-layered maps. It is possible to prove the isomorphism of the group (denoted by ) obtained in this way with the original group G. One undeniable advantage of working with instead of G is that we have eliminated the freedom to choose different representations of the same element of the group G, as now different maps correspond to different group elements. The next (and crucial) step in building the theory is the introduction of the so-called canonical form of each element of : that is, the selection of a specific distinguished path for each map.
3.2. Canonical and Certified Forms
Before proceeding to the (quite counterintuitive) construction of canonical forms, let us try to formulate some motivations for this construction.
The idea of choosing a canonical representative for each one-layered map may seem somewhat useless in a sense—after all, the entire previous section was devoted to constructing equivalence classes from the original elements of the group
G, from which we now want to return to considering specific elements. However, this idea becomes much more appealing if we recall the main idea of working with Burnside groups (which is our ultimate goal). This idea consists of grading the set of relations in such a way that within each rank, the relations satisfy the small cancellation conditions, and the relations in the previous rank are in some sense “small” compared to the subsequent ranks. In this case, the van Kampen diagrams, in general, begin to resemble the one shown in
Figure 9:
Cells of each specific rank are adjacent to each other not “ideally” but with layers of cells of lower rank in between. In such a situation, despite the fact that the higher rank satisfies the small cancellation condition, we cannot make any statements (in the spirit of Lemma 1) about the structure of the entire diagram as a whole because cells of higher rank do not abut each other closely.
However, let us assume that we have brought all the relations of rank 2 to canonical form with respect to rank 1 and repeated this operation inductively for all ranks. In this case, the boundaries of cells of the same rank, separated by a thin layer of cells of lower rank, will actually coincide since the word corresponding to the common boundary is written in canonical form on both sides. Hence, this word is the same on both sides (which means that we have chosen the same path on the one-layer map from both sides). Then, we would find that cells of higher ranks are actually directly glued to each other whenever they are close enough, allowing us to manipulate such structures much like ordinary small cancellation groups.
Now let us proceed directly to the formal construction. Let us consider a one-layer map (see diagram 8) of a -canonical word. The idea is to choose one of the two horizontal segments—alternative paths—for each pair of segments and consider the path that goes along the selected segments as the canonical form of the diagram. We use the following criteria for the selection:
Definition 5. For two paths and in a one-layer map situated between bridges and (thus giving the relation ), and given a set of generators , we consider path as preferable if:
is shorter than in terms of the number of symbols.
If and are equal in length, we compare the pairs and (respectively, and ) and compute the difference between their positions in the lexicographical ordering of all of the words of the same length in the alphabet , denoted by (respectively, ). If , we take the smaller of the words and , and if , we take the smaller of of the words and .
If the words and are equal as character strings, we repeat the operation from the previous item for the words and .
It is clear that this definition always allows us to obtain a single preferable path except in the case of : that is, the case . Therefore, in the future, we assume that no relation is a complete square of a word.
Note 1. It is precisely here that the reason for drawing conclusions only about Burnside groups with odd exponents lies—otherwise, even in the first rank, we have a huge number of relations that are squares, which prevent us from unambiguously choosing canonical representatives.
Finally, let us note that we intentionally complicated the definition by including not only the words themselves but also their inverses in the comparison in order to ensure the equivariance of taking the canonical form with taking the inverse element in the group . Indeed, if we did not consider the lexicographic comparison of inverse elements, there could be a situation where when traversing a one-layer map in one direction, we prefer , and when traversing in the opposite direction, we prefer .
Definition 6. The canonical form of a one-layer map is defined as the result of concatenating all the preferable subwords (traversals of the one-layer map) connected by bridges. We denote the canonical form of a one-layer map C as .
Note that for an arbitrary choice of representatives in each equivalence class, it is initially unclear how the canonical forms of the factors are related to the canonical form of the product. However, for our definition of the canonical form, the situation improves significantly. Specifically, we will prove the following lemma:
Lemma 4. , where is the result of conjugating relation by some word.
Thus, in a relation diagram composed of three canonical forms that multiply to give 1, there are at most 4 cells. Moreover, we will show that the diagram of such a “triangle” looks generally like the diagram in
Figure 10.
Proof. To prove this fact, let us first examine how the canonical form can change when one cell is modified in a one-layer map. It is clear that since we choose the preferred option independently in each cell, the canonical form can only change in the initial cell as well as in the case when new cells appear or disappear from our one-layer diagram. The only reason a cell can disappear is if one of its sides becomes too long (longer than
) and therefore ceases to be included in the one-layer map (since we consider only sufficiently short subwords as options for transformations; see Definition 4). However, can the disappearance of cells affect cells in the one-layer map far from the one where the change occurred? Clearly, when moving through the diagram from the changed cell, if a certain cell survives, then all subsequent cells also remain unchanged, so the change can only spread along a sequence of cells, each of which disappears from the diagram. On the other hand, when a neighboring cell disappears, alternative paths are extended by no more than
(because the vertical bridge is now included in one of the alternatives), so a chain of disappearances occurs only when there is a chain of cells for which one of the sides has a relative length of at least
. This situation is depicted in
Figure 11.
Here, the blue path represents the canonical form in the initial map, and the cells in the chain on the right each have a length of at least in the upper part. Then, when the red segment is added to the one-layer map, this chain of cells collapses, disappearing from the map. It is clear that since for each of these cells, the side that disappeared had a length of at least , the canonical form in this area does not change. Moreover, the only place where the canonical form can change is the first surviving cell. Moreover, the change can occur only if the relative lengths of both alternatives in this cell are in the interval , since otherwise, the disappearance of the neighboring cell would not have changed the preferred path.
Thus, despite the fact that a small change in the word can change the canonical form indefinitely far from the point of change, we can somehow “control” these changes: the canonical form changes only in one place, only in the presence of a chain of cells with near-maximal length of one of the paths, and only if at the end of this path there is a cell with relative side lengths close to .
Taking this fact into account, the conclusion of the proof of Lemma 4 becomes obvious: indeed, according to the definition of the product in the group
, we obtain a triangular construction from one-layer maps (see
Figure 12) in which for each of the three sides, the change occurs only in the central (first differing) cell. Thus, the canonical forms of the initial words and their products can differ only in one place on each of the “rays” emanating from the central cell, which proves the statement. □
However, our goal in introducing the canonical form is to achieve even more precise control over possible discrepancies. To achieve this, we will impose an additional condition on the maps under consideration.
First of all, let us note that Lemma 2 implies that all subwords in the maximal
-diagram of a word are arranged sequentially (possibly with small overlaps) and can therefore be ordered. Let us introduce two new constants, which we will denote by
and
, with conditions similar to those imposed on
:
Finally, let us fix a certain aperiodic sequence
of numbers 1 and 2. As a concrete example, the Morse–Thue sequence [
31] can be used, which has the property that for no word
X and symbol
a does the sequence contain a subword of the form
, from which it follows that this sequence does not contain a cube of any word.
Definition 7. A reliable horizontal segment S of relation R in a one-layer map C is defined as follows: there exists a word W equivalent to the word represented by map C (i.e., a path in the map C) such that S is contained in the maximal -diagram of W, the relative length , and for each n, the n-th subwords (respectively, ) in the maximal -diagram encountered when moving left (respectively, right) in the diagram of W have a relative length . In this case, W is called a witness for S.
This definition is not very intuitive, so let us examine it in more detail.
First, note that every preferred horizontal segment (i.e., one that belongs to ) is reliable. Indeed, it is straightforward that serves as a witness for every segment in it (the length of each preferred segment does not exceed , so all subwords in the -diagram have a length of at most ).
Second, notice that the requirement for the existence of a witness is very weak: almost every horizontal segment with a length of or less has the canonical form of the map as a witness. The only situation in which a segment is reliable but the canonical form is not a witness for it is when we have a sequence of horizontal segments of almost exactly the required length (i.e., of a length almost exactly equal to ). Indeed, if the diagram contains a sequence of horizontal segments for which the relative length and for all , , then we have a witness for , but we cannot switch to an alternative, shorter path since the length of each horizontal segment satisfies very strict conditions that do not allow us to add a vertical bridge to take an alternative, globally shorter path. However, if such a situation does not occur, we can always “switch” to the canonical form:
Lemma 5. If there exists a cell R in map C for which the relative length of each horizontal segment does not exceed , then for each horizontal segment to the left of this cell, the existence of a witness is equivalent to the existence of a part of the witness that reaches R. Similarly, for each segment to the right of R, the existence of a witness is equivalent to the existence of a part of the witness that reaches R.
Proof. Since , we can add vertical segments both to the left and to the right, thereby allowing us to switch to the beginning of the shorter horizontal segment in the next cell. Then we take the corresponding part of as a continuation of the witness. □
Definition 8. A map in which every segment is reliable is called certified. The result of leaving only the reliable segments in map C is called the certification result (or certified form) of C and is denoted as .
Now, by introducing separate canonical and certified forms for maps, in the future, we will almost always be interested in their composition: the canonical certified form .
Lemma 6. , where is the result of conjugating relation with some word.
Proof. This lemma is a direct analogue of the previous statement, but it is not obvious itself since diagram certification is a global process, and therefore, the certified form of the product may not coincide with the certified forms of the factors. However, using Lemma 5, we understand that the differences in certified forms occur only in the segment from the triangle center (see
Figure 10) to the point of difference in canonical forms. Indeed, at the point of difference, the length of each horizontal segment does not exceed
, so from Lemma 5, we obtain that all segments farther from the center are either included or not included in the certified forms of both factors and the product simultaneously (since by using a segment with length
, we can switch to either
or
). □
Moreover, we can observe that since all diagram segments are now reliable and thus do not exceed
in terms of relative length, the situation depicted in
Figure 11 is impossible. Therefore, the
only reason for differences in canonical forms can be differences in certified diagrams. However, again, using Lemma 5, this imposes length conditions on all segments between the triangle center and the point of difference. Recall that the sequence
was specifically chosen by us to be aperiodic, which gives us the following fact:
Note 2. If in the conditions of Lemma 6 we have , then the distinguishing points in canonical forms are at most away from the center.
Proof. Indeed, we impose some aperiodic conditions and, moreover, conditions that do not contain subwords of the form , on the lengths of segments of the map between the center of the triangle and the distinguishing point of canonical forms, while the maps of these words are periodic. As a result, the length of the segment on which both conditions hold cannot exceed two periods. □
Here we encounter for the first time the specificity of relations in Burnside groups (periodicity). Since this case is of particular interest to us, let us dwell on it a little more and also prove the following lemma:
Lemma 7. Let and C be a one-layer map. Then for the map , the certified (and therefore canonical) forms have a periodic structure, except possibly for two boundary periods of C on each side.
Proof. If in the certified form C there are no cells (i.e., pairs of alternative paths), then the statement is proven. If at least one cell is present, then the length of each side in it does not exceed . In this case, according to Lemma 5, the witness only needs to reach the first such cell. And since this cell appears in every instance of the map C, the existence of a witness is equivalent for all internal periods (as it is sufficient to reach the nearest copy of this cell on the right and left). □
At this point, we move from constructing the necessary structures for analyzing Burnside groups (and groups with a graded structure of small cancellations) to more applied activities. In the next section, we will consider graded Van Kampen diagrams and apply the apparatus developed in the two previous sections to analyze them.
3.3. Ranking of Relations
Starting from this section, we will finally study the topology of Van Kampen diagrams arising in groups with a graded structure of small cancellations. Here and below, we will usually require : that is, each cell is surrounded by at least ten other cells of the same rank.
The foundation for all subsequent reasoning in this section will be the distribution of cells in the diagram according to their distance from a certain fixed central cell.
More formally, let us fix a cell
; then the distance from each cell
R in the diagram to
is defined as the minimum distance between the vertices corresponding to these cells in the dual graph. The left side of
Figure 13 shows a typical (topological) appearance of the diagram after distributing the cells by distance.
By classical reasoning in small cancellation theory, it can be proved that if all cells in the diagram, except possibly the central cell, satisfy the small cancellation condition with a constant
, then no cell can behave as shown in
Figure 13 in the central or right diagram (otherwise, the cells in the closed region would have too few neighbors in the end).
Lemma 8. No cell from the ring at distance can touch three or more cells at distance . Also, each cell at distance n has at least three neighbors at distance .
Proof. For the first statement: otherwise, one of these cells has one neighbor at distance n, at most two neighbors at distance , and at most two neighbors at distance (we consider a minimal counterexample). For the second statement: otherwise, we have no more than two neighbors at the previous level, no more than two neighbors at the same level, and no more than two neighbors at the next level. Thus there would be a contradiction. □
From Lemma 8, it immediately follows that the number of cells at distance n from a given cell grows exponentially as a function of n.
However, we are interested in the topology of diagrams not only in groups with small cancellation conditions but also in groups where the small cancellation condition holds for each rank of relations separately. In this work, we focus on the case when there are two ranks of relations: . However, generalization to an arbitrary number of ranks can be achieved by trivially repeating all the reasoning presented here. We will use the results of previous sections and bring all the words from to canonical form with respect to the relations from . Now our goal will be to formulate the necessary estimates for, informally speaking, the number of neighbors for each cell of rank 2 in the Van Kampen diagram over G.
Let us formalize the above. So for a Van Kampen diagram consisting of relations of two ranks, we introduce the concept of a derived diagram as follows. Let us introduce a certain ordering of rank 2 cells participating in the diagram and denote them as . Then for each cell of rank 1, distances from it to each of the cells of rank 2 are defined. We call the region of the cell the subdiagram that includes itself as well as all cells for which and all cells for which and . Intuitively, we call the region of the cell the area of the diagram for which is the nearest cell of rank 2, using the introduced ordering to resolve cases of equal distances. The Van Kampen diagram, together with the ordering , the numbers , and the partition into regions, is called the derived diagram.
It is clear that since the relations from are now written in canonical form, the cells of rank 2 cannot contain, informally speaking, too long parts of the relations from . Therefore, the cells of rank 1 cannot be strongly adjacent to a cell of rank 2. More precisely, it will be sufficient for us that the relative length of the common boundary between a cell of rank 1 and rank 2 does not exceed , which means that each such cell of rank 1 has at least five neighbors of rank 1. As mentioned above, we also assume , which means that each cell of rank 1 that does not share a boundary with a cell of rank 2 has at least nine neighbors.
Taking into account the above and using reasoning that completely repeats the case of diagrams with relations of one rank, we conclude that, informally speaking, in the topology of each specific region there are no holes (see
Figure 13). Formally, this means that the subsets of the region formed by the cells of distance
is simply connected for all n.
We are interested in analyzing the boundary between two regions. Before moving on to the analysis of the “big picture”, we will prove a lemma that is quite trivial but plays a key role in the subsequent analysis. Note that due to the regularity of the cell layout structure at a given distance from the center of the region, we can fix a certain direction of traversal and have the ability to talk about the next and previous regions in the traversal order at a given distance from the center.
Now consider a cell R of rank 1 at distance n. Let us find a cell at distance 1 obtained as follows: starting from R, at each step, we choose the first in the traversal order cell adjacent to the current cell and located at a distance one less. Similarly, we find a cell obtained in a similar way but choose at each step the last in the traversal order cell among those adjacent to the current cell.
Then the following lemma holds.
Lemma 9. Cells and are adjacent.
Proof. Let us consider the process of iterative descent by distance to the center of the region. At the first step, we obtain two adjacent cells (a consequence of the first statement of Lemma 8). Furthermore, if at the next step we obtain non-adjacent cells, then in the region denoted by blue in
Figure 14, a cell at the next level has no more than two neighbors, which again contradicts the second statement of Lemma 8. □
Now let us look at the boundary between two regions. The general view is shown on the left side of
Figure 15. Let us first consider the case when the cells of rank 2 for these regions are not close to each other: that is, the boundary between the regions is not a boundary of a rank 2 cell.
Without loss of generality, let us say that the cell of the region on the left has a smaller number. Then with a cell at distance k from the center to the left of the boundary, there can be cells at a distance k or to the right of the boundary. The key fact that allows us to provide estimates of the number of neighbors for this region is the following lemma:
Lemma 10. If the boundary between regions does not pass through the boundary of a rank 2 cell, then in the sequence of distances to the center during motion, there are no (non-strict) local maxima.
Proof. Let us consider a local maximum in the left region (the second case is treated analogously). Suppose it is located at a distance of
k from the center. It is clear that the neighboring cells in the same region have distances to the center of either
or
k (since
is impossible due to local maximality). In this case, the given cell has at most four neighbors in its own region. Hence, this cell has at least five neighbors in the right region (see
Figure 16).
It is clear that each of these cells has a distance to the center of k or . However, in any sequence of 5 numbers k and , there exists a local maximum. Now let us repeat the reasoning for this local maximum, and we obtain that this cell must have at least five neighbors in the left region. However, by construction, it has exactly one. Thus, there is a contradiction. □
Thus, when moving along the boundary between regions, the distance to the center first decreases with each step and then increases with each step, with no more than two repeated distances in between (otherwise we would have a local maximum in a trivial way). This means that for the outermost cell on the boundary, one of the two sequences of cells described in Lemma 9 goes along the boundary (see
Figure 17) until the minimum distance on the boundary is reached. This allows us to prove the following important fact:
Lemma 11. If the boundary between regions does not pass through the boundary of a rank 2 cell, then any shortest path from a cell on this boundary to a cell at a distance of 1 from the center of the region enters one of at most five consecutively located cells at a distance of 1 from the center.
Proof. Let T and B denote the outermost cells on the boundary. It is evident that two cells, in which the leftmost and rightmost paths coming from T respectively enter (denoted by and in the terminology of Lemma 9) are the endpoints of any shortest path to the center starting from any cell on the boundary from T to the local minimum. The same holds for B. It has been previously shown that there is at most one local minimum, which means that there is at most one cell between the pair of cells and the pair , which proves the statement of the lemma. □
Moreover, since each cell at a distance of 1 is an endpoint of a shortest path from a cell on the region boundary, Lemma 11 asserts that the number of boundaries that do not pass through rank 2 cells for a given region must be sufficiently large (since each boundary occupies no more than five cells at a distance of 1 from the center).
We still need to consider the case when the boundary between regions passes directly through the boundary of a rank 2 cell. In this case, we are dealing with the so-called adjacency region:
Definition 9. Let us consider two rank 2 cells and in the Van Kampen diagram. The portion of the diagram consisting of rank 1 cells for which the distance to each of and is one as well as the common segments of the boundaries of and is called the adjacency diagram of and .
It is precisely in the analysis of adjacent rank 2 cells that our previous efforts pay off. Since the rank 2 relations are now written in canonical form with respect to the rank 1 relations, the following statement is true:
Lemma 12. Let us consider the region of adjacency between cells and . Then except for at most two cells on each side of the adjacency region, this region consists entirely of the immediate border between and .
Proof. It is clear that the region of adjacency for and is precisely a one-layer map. Since each of the relations is written in canonical form, the length of each of the alternative sections does not exceed , as we choose the shorter of the alternative sections in the canonical form. According to Lemma 5, in this case, the certified forms match everywhere, except perhaps two sections on each side of the map (the proof is similar to the proof of Lemma 7). Then the canonical forms coincide everywhere, except perhaps three extreme sections on each side (since the canonical form depends only on the geometry of the given cell; two extreme cells may differ in certified form, and one more cell is simultaneously present in both, but the side lengths in it may differ by due to differences in the previous ones). □
Thus, we obtain the following result:
Theorem 2. If the relations within rank 1 satisfy the small cancellation condition with constant , the relations within rank 2 satisfy the small cancellation condition with constant , and the length of the common section of rank 1 and rank 2 cells with respect to a rank 2 cell does not exceed , then for each Van Kampen diagram over , each region has at least neighbors.
Proof. From Lemmas 11 and 12, we deduce that if the border between regions does not have an adjacency region, then it corresponds to at most five rank 1 cells at a distance of 1 from the center of the region. If the border has an adjacency region, then it corresponds to at most two rank 1 cells on each side at a distance of 1 from the adjacency region plus at most three rank 1 cells on each side within the adjacency region plus the relative measure of the immediate common border between rank 2 cells, which gives the required estimate (
Figure 18). □