As is common when looking for differential invariants, we will be satisfied with obtaining a number of independent differential invariants of order k equal to the codimension of an orbit in general position in . In other words, we will generate a differential algebra of differential invariants which, for each order k, contains a transcendence basis for the field of differential invariants of order k. In general, the field of rational differential invariants of order k will be an algebraic extension of the field generated by the transcendence basis. In this section, we will focus on Lagrangian submanifolds of and therefore, in most cases, disregard the differential invariant of order zero corresponding to the information gain.
4.1. From Invariant Symmetric Forms to Scalar Invariants
We will now find the scalar differential invariants. We use , and to construct an invariant frame on .
The symmetric 2-form is nondegenerate, and is used to construct a vector field .
By using again, we turn the symmetric 2-form into a linear map .
We use A to define the additional vector fields for .
We require that constitute a frame on L. This puts conditions on A, and therefore on the 2-jets of L. These conditions hold on a Zariski-open subset of .
Note that all the steps above can be taken without fixing the manifold L if we treat and for as horizontal symmetric forms on . The inverse of is then given by , where is the total derivative. Note that . Thus, and , where are (rational) functions on determined by the algorithm above. These are horizontal vector fields on .
- 4.
The functions are rational, scalar differential invariants.
Remark 4. Note that this idea has previously been used, with slight modifications, when considering subgroups of . Differential invariants of the actions of the Euclidean group and the general linear group on functions were considered in [15,16], respectively. The next step is justifying that we can find, among these differential invariants that we have constructed, a transcendence basis for the field of differential invariants of order k, for each order k.
Lemma 1. There is only one independent differential invariant of order 2. It can be given in coordinates by Proof. Consider the action of on the 2-jet of the information gain at the point . By using translations on V, we may set , so that the 2-jet is given by . The linear and quadratic terms can be encoded in terms of a one-form and a nondegenerate metric, respectively (in fact, by and ). The action by (the stabilizer of 0) preserves the degree of monomials, and we can use it to normalize the quadratic terms to get . Next, we use the stabilizer of the quadratic form, and rotate the expression into . We have used up all the freedom the group gives us, and the 2-jet is brought to normal form. There is only one free constant c, in addition to , so there is at most one invariant of second order in addition to the zero-order information gain, namely the length of the one-form (or its square). □
Before we consider the differential invariants of third order, we consider the invariants of higher order, which is an easier task. At points in general position in , the horizontal vector fields are linearly independent. Notice that the function is a sum of and lower-order terms. Since the coefficients of depend on , the invariants , with , are algebraically independent when restricted to a generic fiber of . This argument is easily extended to , and we obtain the following statement.
Lemma 2. The differential invariants , with and , are algebraically independent. Moreover, for each , the number of independent functions among them, when restricted to a generic fiber of , is equal to the dimension of the fiber.
We deduce from the lemma that the
-action is locally free on
, meaning that the dimension of an orbit in general position in
is equal to
. Since we have
, the codimension of an orbit in general position is given by
Therefore, in addition to the invariant of order two, there exist
algebraically independent differential invariants of order three. We will verify that we have found all of them.
It is clear from the construction of the invariant frame
that we have the relations
Note how this is consistent with the fact that there is only one second-order invariant
. It also follows that there will be relations between
:
In two dimensions this holds trivially, since
is symmetric. In three dimensions the additional relation takes the form
In four dimensions we get two additional relations:
For
we get
relations between the
components of
. The difference is
.
Lemma 3. The algebraic relations between the differential invariants , with , are exactly the relations given by (6). Proof. It is sufficient to prove that there are algebraically independent functions in this set of differential invariants. We will do this by restricting to a suitable -dimensional submanifold in , and show that there are independent functions among the invariants, also after restricting to this submanifold. After the appropriate submanifold is found, the statement of the lemma follows quite easily.
First we restrict the invariants to the fiber of
given by
On this fiber, the expressions for the tensors
and
are significantly simplified:
We restrict further to a submanifold of this fiber, of codimension
, by setting
On this subset, we have
and, in general, the only nonzero components of
are in the
-directions for
. Moreover, the coefficients for
depend only on the variables
and
in addition to the variables of which
depend. This allows for an induction argument, since the expression for
is independent of
. We have
For
we get
These four functions are clearly independent, and thus the lemma is proved in the case
. With an appropriate choice of ordering of the functions
, each new function depends on the same variables as the previous function in addition to
, for
.
Due to the particular form of and , when restricted to our submanifold, it is clear that this type of pattern will continue. By extending the sequence of functions, with one at a time, each variable will be introduced with the function , where and and (this also indicates the appropriate ordering). There are two possible obstructions to this, and we have to justify that they are, in fact, not obstructions.
Firstly, the function will depend on the same variables as the four we found above, in addition to . This new variable is zero on our submanifold, and thus is not independent from the previous ones. However, this is exactly what we want, as we are already aware of the relation . The situation is similar for and , and so on.
Secondly, even though the derivations depend in nontrivial ways on the variables, this fact does not interfere with the pattern. The potential new variables coming from the derivations will always be introduced (to our sequence of functions) with , and these new variables would be and . The first one was introduced already by , and the second is exactly the one that should be introduced here, as it is equal to . The fact that is squared in is a consequence of this. □
These lemmas imply that we have in the following sense constructed a complete set of rational differential invariants.
Theorem 3. For every order k, the field generated by and , where and generates a field of differential invariants with transcendence degree equal to the codimension of an -orbit in general position in .
Let denote the codimension of an -orbit in , in general position, for . This number is the same as the transcendence degree of the field of rational scalar differential invariants of order k. The Hilbert function for the filtered field of differential invariants is defined as for , and . From the discussion above we deduce the following statement.
Theorem 4. The Hilbert function for the field of differential invariants is given by Note that for , the formula for coincides with that for , as both gives 4.
We define the Poincaré function corresponding to the Hilbert function by the series which converges to a rational function for .
Theorem 5. The Poincaré function for the field of differential invariants is given by 4.2. The Differential Algebra of Differential Invariants
The differential algebra of differential invariants is finitely generated (see [
14] and references therein). The invariant horizontal vector fields
act on the differential invariants as derivations, resulting in new differential invariants which, in general, are of higher order. It is clear that we get, by taking invariant derivatives of the
kth-order invariants
, a set of
independent differential invariants of order
, for
(since the coefficients of the derivations
are only of order 3). See for example [
12] (Theorem 5.48). Thus, the algebra of differential invariants can be generated by the differential invariants of order 4, together with the invariant derivations.
Theorem 6. The differential algebra of scalar differential invariants is generated by the invariant derivations and the scalar invariants , , and .
Note that this generating set of differential invariants is not minimal. As explained in in the previous section, some of the invariants are algebraically related to each other. Moreover, many of the invariants can be constructed by computing invariant derivatives of the third-order invariants. In particular, when the algebra of differential invariants can be generated by and the differential invariants of order three.
4.3. Differential Syzygies for
The algebra of differential invariants is not a freely generated differential algebra; there are differential syzygies among the generators. We will find the syzygies in the simplest case, when . This will also let us sharpen Theorem 6 for this particular case.
We have
and
. In order to write the differential syzygies in a relatively compact form, it will be useful to have the following definitions:
When
, the third-order invariants are sufficient to generate the whole algebra. Furthermore, if we compute invariant derivatives of
, we get
This implies that the invariants
are sufficient for generating the algebra of differential invariants, together with
and
. Let us express the differential syzygies relating these generators.
The derivations
satisfy the commutation relation
where
and
. The commutation relation determines some of the differential syzygies. When finding the rest of them, we consider only higher-order invariant derivatives of the form
, where
are non-negative integers.
Invariant derivatives of give differential invariants of order k for while the invariant derivatives of and give differential invariants of order k for . This implies that we get 4 differential invariants of order three, 7 of order four and, in general, of order k for . The Hilbert function is given by for , implying that there are syzygies for .
Since the differential invariants are rational, finding the differential syzygies becomes a completely algebraic problem. The first two differential syzygies (for
) are found with the help of Maple, and they are given by
Notice that the invariants
can be expressed in terms of
and
.
Since only depends on invariant derivatives of , it is clear that the invariant derivatives of and will give additional independent syzygies involving differential invariants of order k for each . Thus, they generate the desired number of differential syzygies. The commutation relation can be used to ensure that the syzygies are written purely in terms of invariants of the form , where I is , or . We get the following theorem.
Theorem 7. The differential algebra of scalar differential invariants is generated by the invariant derivations and , and the scalar differential invariants , and . The differential syzygies are generated by and .
Remark 5. In [5] it was noted that there is a relation between the curvature of and higher moments. Indeed, when the scalar curvature of can be written as