6. Soft Sets with the Baire Property
Definition 27. Let and . Then, is called soft open modulo if there exists such that is congruent to . That is, , which implies and belong to . The set of all soft open sets modulo shall be . We call a soft open set modulo a soft set with the Baire property.
Remark 3. [30] Let and let . Then, has the Baire property if there exists such that , equivalently, if it is of the form , where and . This follows from the fact that if . Proposition 4. Let and let . Then, if , where and .
Proof. Let
. Then,
for some
and
. If
, then
. Therefore,
. Set
. Then,
Conversely, suppose
, where
and
. Set
. Then,
and so
.
Therefore,
The proof is finished. □
Proposition 5. Let and let . If , then .
Proof. Suppose
. Then,
for some
and
. Now,
By Proposition 4,
. □
Proposition 6. Let , for , and let . If , then .
Proof. It follows from Lemmas 15 and 16. □
Theorem 4. For any , constitutes a soft σ-algebra over X. Furthermore, is the soft σ-algebra generated by τ together with .
Proof. Obviously, . Propositions 5 and 6 prove that is a soft -algebra. On the other hand, suppose is the soft -algebra generated by and . Let . Then, for some and . Hence, . For the reverse of the inclusion, since is both in and , so each soft open or soft set of the first category can be written as . Therefore, and thus . Hence, . □
Proposition 7. Let and let . If , then .
Proof. Let . Then, , where and . Therefore, . Evidently, and . Thus, . □
Proposition 8. Let and let . If and , then .
Proof. Let . Then, , where is a soft set in and . By definition, for some soft set over X. By Theorem 4, . Also, one can see that . Consequently, . □
Proposition 9. Let and let . Then, if , where and .
Proof. Suppose . Then, by Remark 3, there exists such that and are in . Set and , we have that .
Conversely, suppose for some and . Therefore, and . By Remark 3, it follows that . □
Proposition 10. Let and let . Then, if , where and .
Proof. It follows from Propositions 4 and 9. □
Proposition 11. Let and let . Then, if , where is a soft set and .
Proof. Let
. By the definition,
for some
and
. By Proposition 1,
is a soft subset of some soft
set of the first category
, say. Put
. Clearly,
is a soft
set. Now, we have
Set
. Since
and
, so
. Additionally,
and
are disjoint. Thus,
, where
is a soft
set and
.
Conversely, if , for some soft set and , by Theorem 4, . □
Proposition 12. Let and let . Then, if , where is a soft set and .
Proof. Let . By Proposition 5, . Therefore, by Proposition 11, , for some soft set and . Thus, . Set and .
Conversely, since is a soft -algebra containing all soft sets and all , hence, the conclusion follows. □
Lemma 18. Let and let . If , then it can be written as , where is soft regular open and .
Proof. Let and . Then, is soft regular open and . If , then . Therefore, . On the other hand, we always have . Thus, . □
Proposition 13. Let and let . If , then it can be written as , where is soft regular open and . Moreover, if is a soft Baire space, such a representation is unique.
Proof. Let
. Then,
, where
and
. By Lemma 18,
, where
is soft regular open and
. Now,
Set
. Obviously,
. Therefore,
We now prove that this representation is unique. Assume
, where
is soft regular open,
, and
. Then,
. This means that
is a soft open set of the first category. Since
is soft Baire, so we must have
. Therefore,
and hence,
. Thus, in this representation, soft regular open is larger than soft open, and each soft regular open is a soft open set. On the other hand, if both
,
are soft regular open, then we have
and
. Thus,
and
. □
Proposition 14. Let and let . Then, if there exists such that is soft clopen in .
Proof. Let . By Propositions 9 and 10, , where , , and . Set . Then, . This proves that is a soft clopen set in .
Conversely, suppose there exists such that is soft clopen in . Put for some soft clopen over X. Evidently, and hence, . □
Proposition 15. Let and let . Then, if .
Proof. Assume . If , by Lemma 10, . On the other hand, assume . Suppose, otherwise that, . By Theorem 1, is of the second category in some nun-null soft open . Since , then there exists a soft point such that . Since , so . Since is of the second category in and implies is of the second category in . But , which is a contradiction. Hence, .
Conversely, assume
. Consider
Since
,
are in
and
(by Lemma 11), then
from Proposition 10. □
Proposition 16. Let and let . Then, if .
Proof. Suppose
. By Proposition 9,
, where
and
. By Proposition 5,
is also in
. By Lemma 12,
and
. By Lemma 11,
and
. Therefore, we obtain that
Since
, so
.
Conversely, assume
. Let
such that for each
with
,
and
are in
. From the following identity
we obtain that
. Since
we chosen arbitrarily, so
. Therefore,
. By the same reason,
. Now,
From the above equation, one can see that
. Thus,
cannot be in
. □
Summing up all the above findings regarding soft sets with the Baire property yields the following conclusion:
Theorem 5. Let and let . The following properties are equivalent:
- 1.
.
- 2.
If , where is soft regular open and .
- 3.
If , where and .
- 4.
If , where and .
- 5.
If , where and .
- 6.
If , where is a soft set and .
- 7.
If , where is a soft set and .
- 8.
If there exists such that is soft clopen in .
- 9.
.
- 10.
.
Proposition 17. Let and let . If such that no soft point belongs to , Then, .
Proof. such that it not of the first category at any . This means that . By Theorem 5 (9), , i.e., . On the other hand, by Lemma 13 (2), . The latter statements imply that . By Lemma 10, . □
Proposition 18. Let and let . If and disjoint with , then .
Proof. Suppose . Since , so . By Lemma 11, . Therefore, . By Proposition 16, . Thus, . □
Definition 28. Let . The soft σ-algebra generated by τ is called a soft Borel σ-algebra and is denoted by . Members of are called soft Borel sets.
By Theorems 4 and 5,
includes
,
, all soft
sets, all soft
sets,
,
, and
. Consequently,
. That is, each soft Borel set is a soft set of the Baire property. The converse is not true in general. By Lemma 3, we can recall an example in classical topology. It is known that there are infinitely many subsets of the Cantor set that are not Borel. Any of such sets can be regarded as a soft set, which serves as a counterexample; for more details, see [
39].
Theorem 6. Let . If τ has a countable soft base, then , where .
Proof. Let have a countable soft base. Since is a soft -ideal, by Lemma 7, soft open set with respect to are of the form , where and and soft closed set with respect to are of the form , where and . Therefore, . Since is the smallest soft -algebra containing , so .
Conversely, let
. By Proposition 10,
, where
and
. Now, we have
Clearly,
is soft
-closed. On the other hand,
is soft
-open since
and by Lemma 9,
is soft
-closed. Since
contains all soft
-open and soft
-closed set, and is closed under finite soft intersections, hence
. Thus,
. Consequently,
. □
This mission is completed by the diagram at the end of this work, which displays the relationships between the previously mentioned soft sets. We encourage that the reader compare
Figure 1 here with Figure 1 in [
40].
Generally, none of the arrows in
Figure 1 is reversible, it is shown in the following example:
Example 1. Let be the set of real numbers and β be a set of parameters. Let τ be the soft topology on generated by . The soft set is a soft open set modulo soft nowhere dense but neither soft open, soft closed, nor soft nowhere dense. While is a soft set with the Baire property but not soft open set modulo soft nowhere dense.