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Reply

Reply to Bektaş, S. Comment on “Ioannidou, S.; Pantazis, G. Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra. ISPRS Int. J. Geo-Inf. 2020, 9, 494”

by
George Pantazis
and
Stefania Ioannidou
*
School of Rural, Surveying and Geoinformatics Engineering, National Technical University of Athens, 15780 Athens, Greece
*
Author to whom correspondence should be addressed.
ISPRS Int. J. Geo-Inf. 2024, 13(10), 366; https://doi.org/10.3390/ijgi13100366
Submission received: 25 January 2024 / Revised: 27 August 2024 / Accepted: 10 October 2024 / Published: 18 October 2024

Abstract

:
The comment disputes some of the inferences in the paper “Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra”, published in this journal. The key points in the dissent are the following: (1) The number of unknown parameters in the reverse transformation problem using dual quaternions. (2) The reliability of both data and the results. (3) There should be no differences between Euler angles and quaternion methods. Our response is summarized as follows: (1) The problem can be solved using either eight or nine unknown parameters. (2) All the data and results are real. (3) There should be differences between methods because of different calculations.

1. Introduction

This is a response to Mr. Sebahattin Bektas [1] who rejected certain allegations made in the article “Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra” [2].
The original article was not intended to misinform or complicate the mathematical background and theory of the Helmert transformation problem. The main purpose was to compare the methods of determining the transform parameters using either Euler angles or quaternions. It is important to note that when the article was published (2020), the literature on dual quaternions was limited, so the research and comparison of methods were based on what was available at the time. The literature used was primarily by Kenwright, B. in 2012; Jia, Y.B. in 2013; Zeng, H. et al. in 2018 and Jitka, P. in 2011; [3,4,5,6].
Below are clear explanations of the comments received. The whole reply is organized according to Bektas’s three concerns:
  • The number of unknown parameters.
  • The reliability of both data and the results.
  • The differences between the methods used.

2. Helmert Transformation Problem and Unknown Parameters

As mentioned in the original paper (page 3—paragraph 2.1), the Helmert transformation problem is one of the most well-known transformation methods between two systems in the world [2]. More specifically, for two systems (P) and (P′), and for each point p i = x i , y i , z i Τ and p i = x i , y i , z i T , respectively, the following relation holds [2]:
p i = t + λ · R f · p i , i = 1 , , m
where t = t x , t y , t z T : the shift vector (translation parameters); λ: the scale factor; and R f is the rotation matrix through axis xyz (rotation parameters).
When using the Euler angles, there are seven unknown parameters: three angles, three translations and one scale factor. On the contrary, when using the quaternion method to calculate the rotation matrix, quaternions are used. The matrix is calculated by the following Equation (2):
R = q 0 2 q T . q · I 3 + 2 · ( q · q T + q 0 · C ( q ) )
where I3 is the 3 × 3 identity matrix and
q = ( q 0 , q 1 , q 2 , q 3 )   or   q = q 0 + q 1 · i + q 2 · i + q 3 · k = q 0 + q
is a quaternion and matrix
C q = 0 q 3 q 2 q 3 0 q 1 q 2 q 1 0
As a result, there are eight unknown parameters: the quaternion q for the rotation matrix, three translations and one scale factor [2].
When using dual quaternion algebra, dual quaternions are used to calculate the transformation problem. The translation and rotation properties for the unit dual quaternion are defined as q r = r and d = t · r , with r being the unit quaternion that represents the rotation and t = 0 , t x , t y , t z the quaternion that represents the translation. In this case, the rotation matrix uses Equation (2) for quaternion r and matrices Q ( r ) and W ( r ) for greater convenience [2].
So, the final transformation relation arises where the required quaternions r and d are present:
p i = 2 · W · r T · d + λ · W r T · Q r · p i , i = 1 , , m
The two additional constraints for unity ( r 1 2 + r 2 2 + r 3 2 + r 4 2 = 1 )   and orthogonality ( r 1 d 1 + r 2 d 2 + r 3 d 3 + r 4 d 4 = 0 ) that Prof. Bektas mentioned were already used when the Helmert transformation model using dual quaternions was presented, according to Zeng, H. et al. [5]. So, in this research, the final equation, mentioned above, is used.
In the original article, there were nine unknown parameters presented: four for each quaternion and one for the scale factor. According to the received comment, there must be eight unknown parameters, four for each quaternion with the scale factor included in the quaternions ( λ = r 0 2 + r 1 2 + r 2 2 + r 3 2 ), which is also correct [7,8]. However, there are some studies that calculate the scale factor independently of the rotation angles and translation [5].
In the article “Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra”, the scale factor is calculated in the adjustment model, using observation equations:
f ο i = 2 d 0 r 0 2 d 3 r 1 2 d 1 r 3 + 2 d 2 r 2
f x i = 2 d 1 r 0 2 d 3 r 2 + 2 d 0 r 3 2 d 2 r 1 + λ x i r 0 2 + r 1 2 r 2 2 r 3 2 2 λ y i r 0 r 3 r 1 r 2 + 2 λ z i ( r 0 r 2 + r 1 r 3 ) x i
f y i = 2 d 1 r 1 2 d 3 r 3 2 d 0 r 2 + 2 d 2 r 0 + 2 λ x i r 0 r 3 + r 1 r 2 2 λ y i r 0 2 + r 1 2 r 2 2 + r 3 2 2 λ z i ( r 0 r 1 r 2 r 3 ) y i
f z i = 2 d 0 r 1 + 2 d 1 r 2 + 2 d 3 r 0 + 2 d 2 r 3 2 λ x i r 0 r 2 r 3 r 1 + 2 λ y i r 0 r 1 + r 2 r 3 λ z i r 0 2 + r 1 2 + r 2 2 r 3 2 z i
For the least squares method, partial derivatives are calculated using the equations in Appendix A. Additionally, the starting value for the scale factor is calculated from the distances between the known points.

3. Reliability of Data and Results

The purpose of this article is not to keep anything hidden regarding the data or results. Both of them are real and were already sent to the journal along with the mathematical model. Some of the equations used are also presented in this reply, and all of them are attached in Appendix A. Additionally, the original data from the microcosm, macrocosm and intermediate distances are also presented in Appendix B.

4. Differences between Euler Angles and Quaternion Methods

Since ancient times, mathematicians have used Euler angles and quaternions to calculate rotation matrices in 3D space. According to the received comment, these two methods can lead to the same results when it comes to the Helmert transformation problem. However, this is impossible in the reverse problem, as there are significant differences in the calculation of rotation angles, which are transferred to the transformation problem. All these differences are presented here in detail.

4.1. Differences in Rotation Matrices

The rotation angles around the x, y, z axis are called Euler angles, and they are measured clockwise, using the right-hand rule [9], The sequence of Euler angles and the order of the axes in which the rotation takes place significantly determine the final result, as there are 27 different combinations. One of the most well-known combinations is the “xyz” sequence, where a rotation is made first around the x-axis, then around y and finally around z. As a result, the 3D rotation matrix is the multiplication of the rotation matrices of each axis and presented in the following Equation (8):
R x y z = c o s β · c o s γ c o s β · s i n γ s i n β s i n α · s i n β · c o s γ c o s α · s i n γ s i n α · s i n β · s i n γ + c o s α · c o s γ s i n α · c o s β c o s α · s i n β · c o s γ + s i n α · s i n γ c o s α · s i n β · s i n γ s i n α · c o s γ c o s α · c o s β
On the other hand, quaternions can be interpreted as a convenient mathematical notation for representing the orientations and rotations of objects in three dimensions.
The most important difference between Euler angles and quaternions is the problem of singularities, which appears when calculating rotation angles using rotation matrices. This problem arises because a set of Euler angles can lead to the loss of one degree of freedom. In contrast, quaternions provide a more compact and efficient representation of rotations and are not susceptible to this problem [6,10,11].
For a single quaternion ( q = q 0 + q = c o s θ + u ^ · s i n θ ) and for each vector v є R 3 , the quaternion rotation operator is defined and presented in the following Equation (9):
L q v = q · v · q * = q 0 2 q 2 · v + 2 q   · v · q + 2 · q 0 · q × v
and is equivalent to the geometric rotation of the vector by an angle 2θ, with the axis of rotation in the direction of u.
Additionally, the rotation of a 3D vector t around a specific axis and according to Equation (9) has the following result:
t = Q u ·   t ·   Q u *
where u represents the axis around which the vector is rotated. Based on this axis, the following equations are created per case:
Q i = Q X = cos a 2 + s i n α 2 · i + s i n 0 2 · j + s i n 0 2 · k = cos a 2 + s i n α 2 · i  
Q j = Q Y = cos β 2 + s i n 0 2 · i + s i n β 2 · j + s i n 0 2 · k = cos β 2 + s i n β 2 · j
Q k = Q Z = cos γ 2 + s i n 0 2 · i + s i n 0 2 · j + s i n γ 2 · k = cos γ 2 + s i n γ 2 · k
In order to generalize this relation to all three axes, the vector t is as follows:
t = R Q x y z ·   t
and the rotation matrix using quaternions is as follows:
R Q x y z = q 0 2 + q 1 2 q 2 2 q 3 2 2 · q 1 · q 2 2 · q 0 · q 3 2 · q 1 · q 3 + 2 · q 0 · q 2 2 · q 0 · q 3 + 2 · q 1 · q 2 q 0 2 q 1 2 + q 2 2 q 3 2 2 · q 0 · q 1 + 2 · q 2 · q 3 2 · q 0 · q 2 + 2 · q 1 · q 3 2 · q 0 · q 1 + 2 · q 2 · q 3 q 0 2 q 1 2 q 2 2 + q 3 2
For example, given a rotation matrix R in Equation (16), the angles α, β and γ per axis can be calculated.
R x y z = 0.5 0.5 0.7071 0.1464 0.8536 0.5 0.8536 0.1464 0.5
According to the elements of the matrix [12] and Equation (8), possible values for rotation angles are calculated:
  • The possible values for β are β 1 = sin 0.7071 = 45 ° and β 2 = 180 ° β 1 = 135 ° .
  • The corresponding values of α are a 1 = a t a n 2 0.5 cos 45 ° , 0.5 cos 45 ° = 45 ° and a 2 = a t a n 2 0.5 cos 135 ° , 0.5 cos 135 ° = 135 ° .
  • The values for γ are γ 1 = a t a n 2 0.5 cos 45 ° , 0.5 cos 45 ° = 45 ° and γ 2 = a t a n 2 0.5 cos 135 ° , 0.5 cos 135 ° = 135 ° .
As a result, the solutions are 45 ° , 45 ° , 45 ° and 135 ° , 135 ° , 135 ° , but there is always one sequence of rotations that results in the same orientation of an object. It is found that even if the rotations are different, the rotation matrices are the same. On the other hand, the same orientation can be represented by two quaternions, only if q 1 = ± q 2 or q 1 · q 2 = ± 1 .

4.2. Differences in Helmert Transformation Problem

When calculating the Helmert transformation problem, and trying to calculate the unknown transformation parameters, the results in each method (Euler angles, quaternion, dual quaternion) can also be different.
Even if the Least Square Calculating Method is the same, as are the starting values used, the observation equations are different in each method, so the results can be different.
More specifically, the observation equations used in the Euler angle method are as follows:
f x i = x i t x + λ · x i · b 2 a 2 + c 2 1 + λ · y i · 2 c a b λ · z i · 2 b + a c a 2 + b 2 + c 2 + 1
f y i = y i t y + λ · x i · 2 c + a b + λ · y i · a 2 b 2 + c 2 1 + λ · z i · 2 a b c a 2 + b 2 + c 2 + 1
f z i = z i t z + λ · x i · 2 b a c λ · y i · 2 a + b c + λ · z i · ( a 2 c 2 + b 2 1 ) a 2 + b 2 + c 2 + 1
The values a, b and c are calculated instead of angles according to the following equation.
R = I C 1 · I + C   w h e r e   C = 0 c b c 0 a b a 0
and the observation equations used in the quaternion method are as follows:
f x i = x i t x λ x i q 0 2 + q 1 2 q 2 2 q 3 2 + 2 λ y i q 0 q 3 q 1 q 2 2 λ z i q 0 q 2 + q 1 q 3
f y i = y i t y 2 λ x i q 0 q 3 + q 1 q 2 λ y i q 0 2 q 1 2 + q 2 2 q 3 2 + 2 λ z i ( q 0 q 1 q 2 q 3 )
f z i = z i t z + 2 λ x i q 0 q 2 q 1 q 3 2 λ y i q 0 q 1 + q 2 q 3 λ z i q 0 2 q 1 2 q 2 2 + q 3 2
and the observation equations used in the dual quaternion method are presented in Equations (4)–(7). For the matrix of coefficients of the parameters of interest, the partial derivatives are calculated using the equations in Appendix A.
As a result, each matrix is different in any case, because they estimate different values, so the results cannot be the same, even if they were derived from the Helmert similarity transformation. The only constraints are between the quaternion’s elements, but in each case, λ is used for the scale factor, and non-unit quaternions are used for the rotations.

5. Results

The differences between Euler angles and quaternions also affect their practical applications. Euler angles are often used in simple applications where computational efficiency is not critical, such as in some classical mechanics problems and in the initial stages of learning about rotations. Quaternions, however, are widely used in aerospace engineering, robotics, computer graphics and other fields where the robust and efficient computation of 3D rotations is essential.
To sum up, the main differences between Euler angles and quaternion methods in the Helmert transformation problem include the following:
  • Euler angles are subject to ambiguity, while quaternions are not.
  • Quaternions provide a more efficient and compact representation of rotations.
  • The practical applications of each method differ significantly, with quaternions being preferred in fields requiring robust 3D rotation computations.

6. Conclusions

The primary purpose of the original paper [2] was to compare the different calculation methods in the Helmert transformation problem, using the existing references. This uses a huge mathematical background which is not analyzed in detail, in order to have space for the statistical analysis and the results. In this reply, there are further details about the equations used.
For dual quaternions, the references were limited, so we worked with some of them. The scale factor can be calculated in two different ways, but both can lead to scientifically correct results.
All the results were statistically tested and examined in detail. The code used was also examined line by line; it is all real and was already sent to the journal. There was no intention of keeping the code or the data hidden.
Finally, each method can lead to different results because the least square method uses different equations and matrices for the Euler, quaternion and dual quaternion methodology. Quaternions were created to solve calculation problems in Euler angles so that they could lead to better results.
So, this response aims to clarify the points raised by Mr. Sebahattin Bektas and to highlight the differences between Euler angles and quaternion methods in solving the Helmert transformation problem. Both methods have their own merits and specific applications, but it is crucial to understand their differences and the contexts in which each method is best suited. Our research was conducted based on the available literature at the time, and we welcome a further discussion and exploration of these methods in future studies.

Supplementary Materials

The following supporting information can be downloaded at: https://www.mdpi.com/article/10.3390/ijgi13100366/s1.

Author Contributions

Conceptualization, George Pantazis and Stefania Ioannidou; methodology, George Pantazis and Stefania Ioannidou; software, Stefania Ioannidou; validation, George Pantazis and Stefania Ioannidou; formal analysis, Stefania Ioannidou; investigation, George Pantazis and Stefania Ioannidou; resources, data curation, Stefania Ioannidou; writing—original draft preparation, Stefania Ioannidou; writing—review and editing, George Pantazis and Stefania Ioannidou; visualization, Stefania Ioannidou; supervision, George Pantazis; project administration, George Pantazis. All authors have read and agreed to the published version of the manuscript.

Funding

This research received no external funding.

Data Availability Statement

Supporting data are available in Supplementary Materials.

Conflicts of Interest

The authors declare no conflicts of interest.

Appendix A

In this appendix, partial derivative equations, for each method, are presented.

Appendix A.1. Partial Derivatives for Euler Angle Method

f x i a = 0 f x i t x = 1 f x i x i = 1 f x i x i = λ f x i λ = x i + c   y i b   z i
f x i b = z i + t z λ z i f x i t y = c f x i y i = c f x i y i = λ   c
f x i c = y i t y + λ y i f x i t z = b f x i z i = b f x i z i = λ b
f y i a = z i t z + λ z i f y i t x = c f y i x i = c f y i x i = λ   c f y i λ = c   x i y i + a z i
f y i b = 0   f y i t y = 1 f y i y i = 1 f y i y i = λ
f y i c = x i + t x λ x i f y i t z = a f y i z i = α f y i z i = λ   α
f z i a = y i + t y λ y i f z i t x = b f z i x i = b f z i x i = λ   b f z i λ = b x i a y i z i
f z i b = x i t x + λ x i f z i t y = a f z i y i = a f z i y i = λ   α
f z i c = 0 f z i t z = 1 f z i z i = 1 f z i z i = λ

Appendix A.2. Partial Derivatives for Quaternion Method

f x i q 0 = 2 λ x i q 0 + 2 λ y i q 3 2 λ z i   q 2 f x i x i = λ ( q 0 2 + q 1 2 q 2 2 q 3 2 ) f x i t x = 1 f x i x i = 1
f x i q 1 = 2   λ   x i   q 1 2   λ   y i   q 2 2   λ   z i   q 3 f x i y i = 2   λ q 1 q 2 + 2   λ q 0 q 3 f x i t y = 0 f x i y i = 0
f x i q 2 = 2   λ   q 2 2   λ   y i   q 1 2   λ   z i   q 0 f x i z i = 2   λ q 1   q 3 2 λ q 0   q 2 f x i t z = 0 f x i z i = 0
f x i q 3 = 2   λ   x i   q 3 + 2   λ   y i   q 0 2   λ   z i   q 1
f x i λ = x i ( q 0 2 + q 1 2 q 2 2 q 3 2 ) 2   y i ( q 1 q 2 q 0 q 3 ) 2   z i ( q 1 q 3 + q 0 q 2 )
f y i q 0 = 2   λ   x i   q 3 2   λ   y i   q 0 + 2   λ   z i   q 1 f y i x i = 2   λ   q 1 q 2 2   λ   q 0   q 3 f y i t x = 0 f y i x i = 0
f y i q 1 = 2   λ   x i q 2 + 2   λ y i   q 1 + 2   λ   z i   q 0 f y i y i = λ   q 0 2 q 1 2 + q 2 2 q 3 2 f y i t y = 1 f y i y i = 1
f y i q 2 = 2   λ x i   q 1 2   λ   y i   q 2 2   λ   z i   q 3 f y i z i = 2   λ   q 2 q 3 + 2   λ   q 0 q 1     f y i t z = 0 f y i z i = 0
f y i q 3 = 2   λ   x i q 0 + 2   λ   y i   q 3 2   λ   z i   q 2
f y i λ = y i q 0 2 q 1 2 + q 2 2 q 3 2 2 x i   q 1 q 2 + q 0 q 3 2 z i ( q 2 q 3 q 0 q 1 )
f z i q 0 = 2   λ x i   q 2 2   λ y i q 1 2   λ z i q 0 f z i x i = 2   λ   q 1 q 3 + 2   λ   q 0 q 2 f z i t x = 0 f z i x i = 0
f z i q 1 = 2   λ x i   q 3 2   λ y i   q 0 + 2   λ z i   q 1 f z i y i = 2   λ   q 2 q 3 2   λ q 0 q 1 f z i t y = 0 f z i y i = 0
f z i q 2 = 2   λ x i   q 0 2   λ y i   q 3 + 2   λ z i   q 2 f z i z i = λ ( q 0 2 q 1 2 q 2 2 + q 3 2 )   f z i t z = 1 f z i z i = 1
f z i q 3 = 2   λ x i   q 1 2   λ y i   q 2 2   λ z i   q 3
f z i λ = z i ( q 0 2 q 1 2 q 2 2 + q 3 2 ) 2   x i ( q 1 q 3 q 0 q 2 ) 2   y i ( q 2 q 3 + q 0 q 1 )

Appendix A.3. Partial Derivatives for Dual Quaternion Method

f ο i r 0 = 2 d 0 f ο i r 1 = 2 d 3 f ο i r 2 = 2 d 2 f ο i r 3 = 2 d 1 f ο i λ = 0 f ο i x i = 0 f ο i y i = 0 f ο i z i = 0
f ο i d 0 = 2 r 0 f ο i d 1 = 2 r 3 f ο i d 2 = 2 r 2 f ο i d 3 = 2 r 1 f ο i x i = 0 f ο i y i = 0 f ο i z i = 0
f x i r 0 = 2 d 1 + 2 λ x i r 0 2 λ y i r 3 + 2 λ z i r 2 f x i d 0 = 2 r 3 f x i x i = λ ( r 0 2 + r 1 2 r 2 2 r 3 2 ) f x i x i = 1
f x i r 1 = 2 d 2 + 2 λ x i r 1 + 2 λ y i r 2 + 2 λ z i r 3 f x i d 1 = 2 r 0 f x i y i = 2 λ ( r 0 r 3 r 1 r 2 ) f x i y i = 0
f x i r 2 = 2 d 3 2 λ x i r 2 + 2 λ y i r 1 + 2 λ z i r 0 f x i d 2 = 2 r 1 f x i z i = 2 λ ( r 0 r 2 + r 1 r 3 ) f x i z i = 0
f x i r 3 = 2 d 0 2 λ x i r 3 2 λ y i r 0 + 2 λ z i r 1 f x i d 3 = 2 r 2
f x i λ = x i ( r 0 2 + r 1 2 r 2 2 r 3 2 ) 2 y i ( r 0 r 3 r 1 r 2 ) + 2 z i ( r 0 r 2 + r 1 r 3 )
f y i r 0 = 2 d 2 + 2 λ x i r 3 + 2 λ y i r 0 2 λ z i r 1 f y i d 0 = 2 r 2 f y i x i = 2 λ ( r 0 r 3 + r 1 r 2 )   f y i x i = 0
f y i r 1 = 2 d 1 + 2 λ x i r 2 2 λ y i r 1 2 λ z i r 0 f y i d 1 = 2 r 1 f y i y i = λ r 0 2 + r 1 2 r 2 2 + r 3 2   f y i y i = 1
f y i r 2 = 2 d 0 + 2 λ x i r 1 + 2 λ y i r 2 + 2 λ z i r 3 f y i d 2 = 2 r 0 f y i z i = 2 λ ( r 0 r 1 r 2 r 3 ) f y i z i = 0
f y i r 3 = 2 d 3 + 2 λ x i r 0 2 λ y i r 3 + 2 λ z i r 2 f y i d 3 = 2 r 3
f y i λ = 2 x i ( r 0 r 3 + r 2 r 1 ) y i ( r 0 2 + r 1 2 r 2 2 + r 3 2 ) 2 z i ( r 0 r 1 r 2 r 3 )
f z i r 0 = 2 d 3 2 λ x i r 2 + 2 λ y i r 1 + 2 λ z i r 0 f z i d 0 = 2 r 1 f z i x i = 2 λ ( r 0 r 2 r 1 r 3 )   f z i x i = 0
f z i r 1 = 2 d 0 + 2 λ x i r 3 + 2 λ y i r 0 2 λ z i r 1 f z i d 1 = 2 r 2 f z i y i = 2 λ ( r 0 r 1 + r 2 r 3 ) f z i y i = 0
f z i r 2 = 2 d 1 2 λ x i r 0 + 2 λ y i r 3 2 λ z i r 2 f z i d 2 = 2 r 3 f z i z i = λ r 0 2 + r 1 2 + r 2 2 r 3 2 f z i z i = 1
f z i r 3 = 2 d 2 + 2 λ x i r 1 + 2 λ y i r 2 + 2 λ z i r 3 f z i d 3 = 2 r 0
f z i λ = 2 x i r 0 r 2 r 3 r 1 + 2 y i ( r 0 r 1 + r 2 r 3 ) z i ( r 0 2 + r 1 2 + r 2 2 r 3 2 )

Appendix B

The original data from the microcosm are as follows.
0.14330.15490.10460.39620.26500.1563
0.25470.25350.31430.35500.09350.2247
0.09480.37500.20660.57350.20630.2763
0.21330.45630.07350.62440.05860.3962
0.36490.42490.35680.51230.47360.1266
The original data from the macrocosm are as follows.
99.63370.47562.586250.32545.704110.655
110.555160.69045.725345.62830.606201.322
170.653120.79398.893360.428106.925104.251
220.444185.625179.676432.338158.654125.173
299.547179.586155.493470.77652.21432.954
The original data from intermediate distances are as follows.
9.6363.7221.42658.2528.1013.511
11.3258.5735.49351.7932.9114.417
35.6469.4579.63589.4659.2878.475
38.9535.93310.72578.3275.2546.325
26.7242.4672.04175.9581.5261.166

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Pantazis, G.; Ioannidou, S. Reply to Bektaş, S. Comment on “Ioannidou, S.; Pantazis, G. Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra. ISPRS Int. J. Geo-Inf. 2020, 9, 494”. ISPRS Int. J. Geo-Inf. 2024, 13, 366. https://doi.org/10.3390/ijgi13100366

AMA Style

Pantazis G, Ioannidou S. Reply to Bektaş, S. Comment on “Ioannidou, S.; Pantazis, G. Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra. ISPRS Int. J. Geo-Inf. 2020, 9, 494”. ISPRS International Journal of Geo-Information. 2024; 13(10):366. https://doi.org/10.3390/ijgi13100366

Chicago/Turabian Style

Pantazis, George, and Stefania Ioannidou. 2024. "Reply to Bektaş, S. Comment on “Ioannidou, S.; Pantazis, G. Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra. ISPRS Int. J. Geo-Inf. 2020, 9, 494”" ISPRS International Journal of Geo-Information 13, no. 10: 366. https://doi.org/10.3390/ijgi13100366

APA Style

Pantazis, G., & Ioannidou, S. (2024). Reply to Bektaş, S. Comment on “Ioannidou, S.; Pantazis, G. Helmert Transformation Problem. From Euler Angles Method to Quaternion Algebra. ISPRS Int. J. Geo-Inf. 2020, 9, 494”. ISPRS International Journal of Geo-Information, 13(10), 366. https://doi.org/10.3390/ijgi13100366

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