Structural Damage Assessment Using Multiple-Stage Dynamic Flexibility Analysis
Abstract
:1. Introduction
2. Theoretical Development
2.1. Stage I: Judging Whether Damage Occurs by the Rank Analysis of Dynamic Flexibility Change
2.2. Stage II: Determining Damage Locations by the Minimum Rank of Flexibility Correlation Matrices
2.3. Stage III: Quantifying Damage Extent
3. Numerical Example
3.1. Single Damage Condition
3.2. Multiple Damage Condition
4. Verification by the Experimental Data of Reference
4.1. Damage Case 1
4.2. Damage Case 2
5. Conclusions
Author Contributions
Funding
Institutional Review Board Statement
Informed Consent Statement
Data Availability Statement
Conflicts of Interest
References
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Frequency Number | Undamaged | Single Damage | Multiple Damage |
---|---|---|---|
1 | 43.4 | 43.0 | 42.9 |
2 | 109.7 | 108.8 | 109.5 |
3 | 150.9 | 150.9 | 150.6 |
4 | 257.7 | 257.4 | 252.9 |
5 | 338.9 | 337.5 | 336.7 |
Element Number | Singular-Values (×10−6) | Identified Column Rank |
---|---|---|
1 | 0.0173, 0.0068 | 2 |
2 | 0.1009, 0.0111 | 2 |
3 | 0.0171, 0.0059 | 2 |
4 | 0.0174, 0.0063 | 2 |
5 | 0.0168, 0.0054 | 2 |
6 | 0.0987, 0.0057 | 2 |
7 | 0.0164, 0.0053 | 2 |
8 | 0.0333, 0.0093 | 2 |
9 | 0.0161, 0.0054 | 2 |
10 | 0.0912, 0.0000 | 1 |
11 | 0.0159, 0.0055 | 2 |
12 | 0.0561, 0.0097 | 2 |
13 | 0.0159, 0.0053 | 2 |
14 | 0.0726, 0.0049 | 2 |
15 | 0.0160, 0.0049 | 2 |
16 | 0.0739, 0.0106 | 2 |
17 | 0.0162, 0.0045 | 2 |
18 | 0.0477, 0.0075 | 2 |
19 | 0.0164, 0.0043 | 2 |
20 | 0.0775, 0.0117 | 2 |
21 | 0.0167, 0.0045 | 2 |
22 | 0.0243, 0.0084 | 2 |
23 | 0.0169, 0.0050 | 2 |
24 | 0.0170, 0.0073 | 2 |
25 | 0.0171, 0.0059 | 2 |
26 | 0.0160, 0.0025 | 2 |
27 | 0.0173, 0.0069 | 2 |
5% Noise Level | 10% Noise Level |
---|---|
Stage I: (1) The eigenvalues of can be calculated as: 0.6228 × 10−7, 0.0076 × 10−7, 0.0025 × 10−7, 0.0006 × 10−7, 0, 0, …. (2) The rank of can be determined as 1 due to 0.0076/0.6228 = 1.22% < 5%. (3) It can be judged that only one element is damaged. | Stage I: (1) The eigenvalues of can be calculated as: 0.6324 × 10−7, 0.0142 × 10−7, 0.0090 × 10−7, 0.0034 × 10−7, 0, 0, …. (2) The rank of can be determined as 1 due to 0.0142/0.6324 = 2.25% < 5%. (3) It can be judged that only one element is damaged. |
Stage II: (1) The ratio graph of singular values for the correlation matrices follows: (2) Element 10 can be determined as the damaged bar according to the minimum value in the ratio graph. | Stage II: (1) The ratio graph of singular values for the correlation matrices follows: (2) Element 10 can be determined as the damaged bar according to the minimum value in the ratio graph. |
Stage III:The damage extent can be calculated as = 18.87%. | Stage III:The damage extent can be calculated as = 20.32%. |
Element Combination | Singular-Values (×10−7) | Identified Column Rank |
---|---|---|
1 and 2 | 1.006, 0.133, 0.058 | 3 |
3 and 5 | 0.1648, 0.0633, 0.0322 | 3 |
4 and 6 | 0.9844, 0.0889, 0.0577 | 3 |
7 and 8 | 0.3307, 0.0795, 0.0439 | 3 |
14 and 19 | 0.7249, 0.0446, 0.0000 | 2 |
19 and 24 | 0.1604, 0.0685, 0.0336 | 3 |
19 and 26 | 0.1464, 0.0404, 0.0196 | 3 |
5% Noise Level | 10% Noise Level |
---|---|
Stage I: (1) The eigenvalues of can be calculated as: 0.6508 × 10−7, 0.0355 × 10−7, 0.0043 × 10−7, 0.0032 × 10−7, 0, 0, …. (2) The rank of can be determined as 2 due to 0.0355/0.6508 = 5.45% > 5% and 0.0043/0.6508 = 0.66% < 5%. (3) It can be judged that two elements are damaged. | Stage I: (1) The eigenvalues of can be calculated as: 0.6444 × 10−7, 0.0384 × 10−7, 0.0095 × 10−7, 0.0071 × 10−7, 0, 0, …. (2) The rank of can be determined as 2 due to 0.0384/0.6444 = 5.96%>5% and 0.0095/0.6444 = 1.47% < 5%. (3) It can be judged that two elements are damaged. |
Stage II: (1) The ratio graph of singular values for the correlation matrices follows: (2) Elements 14 and 19 can be determined as the damaged bars according to the minimum value in the ratio graph. | Stage II: (1) The ratio graph of singular values for the correlation matrices follows: (2) Elements 14 and 19 can be determined as the damaged bars according to the minimum value in the ratio graph. |
Stage III: The damage extents can be calculated as = 18.34% and = 24.92%. | Stage III: The damage extents can be calculated as = 17.64% and = 34.71%. |
Mode Number | Natural Frequency | Mode Shape |
---|---|---|
1 | = 3.369 | = (0.02118,0.03922,0.048427)T. |
2 | = 9.704 | = (0.048758,0.02031,-0.03923)T |
3 | = 14.282 | = (0.037936,-0.04866,0.022852)T |
Mode Number | Natural Frequency | Mode Shape |
---|---|---|
1 | = 3.259 | = (0.022735,0.039331,0.047594)T |
2 | = 9.485 | = (0.049417,0.017683,-0.03968)T |
3 | = 14.209 | = (0.035798,-0.04982,0.02379)T |
Mode Number | Natural Frequency | Mode Shape |
---|---|---|
1 | = 3.003 | = (0.022172,0.040166,0.047161)T |
2 | = 9.082 | = (0.053402,0.012675,−0.03629)T |
3 | = 13.330 | = (0.031506,-0.05023,0.028513)T |
Proposed Method | Generalized Flexibility Method |
---|---|
Stage I: (1) The eigenvalues of can be calculated as: 7.52 × 10−7, -0.274 × 10−7, -0.012 × 10−7. (2) The rank of can be determined as 1 due to 0.274/7.52 = 3.64% < 5%. (3) It can be judged that only one element is damaged. | The damage extent calculated by the generalized flexibility method follows: |
Stage II: (1) The ratio graph of singular values for the correlation matrices follows: (2) The first floor can be determined as the damaged element according to the minimum value in the ratio graph. | |
Stage III: The damage extent can be calculated as = 13.11%. | The damage extent of the first floor is = 17.89%. |
Proposed Method | Generalized Flexibility Method |
---|---|
Stage I: (1) The eigenvalues of can be calculated as: 2.5344 × 10−6, 0.2196 × 10−6, −0.01053 × 10−6. (2) The rank of can be determined as 2 due to 0.2196/2.5344 = 8.66% > 5% and 0.01053/2.5344 = 0.42% < 5%. (3) It can be judged that two elements are damaged. | The calculated damage extent by the generalized flexibility method follows: |
Stage II: (1) The ratio graph of singular values for the correlation matrices follows. (2) The first and second floors can be determined as the damaged elements according to the minimum value in the ratio graph. | |
Stage III: The damage extent can be calculated as = 33.62% and = 26.9%. | The damage extent of the first and second floors are = 43.02% and = 38.48%. |
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Sun , Y.; Yang, Q.; Peng, X. Structural Damage Assessment Using Multiple-Stage Dynamic Flexibility Analysis. Aerospace 2022, 9, 295. https://doi.org/10.3390/aerospace9060295
Sun Y, Yang Q, Peng X. Structural Damage Assessment Using Multiple-Stage Dynamic Flexibility Analysis. Aerospace. 2022; 9(6):295. https://doi.org/10.3390/aerospace9060295
Chicago/Turabian StyleSun , Yun, Qiuwei Yang, and Xi Peng. 2022. "Structural Damage Assessment Using Multiple-Stage Dynamic Flexibility Analysis" Aerospace 9, no. 6: 295. https://doi.org/10.3390/aerospace9060295
APA StyleSun , Y., Yang, Q., & Peng, X. (2022). Structural Damage Assessment Using Multiple-Stage Dynamic Flexibility Analysis. Aerospace, 9(6), 295. https://doi.org/10.3390/aerospace9060295