1. Introduction
In this paper, we will consider only finite graphs without loops or multiple edges. For graph theoretic terminology we refer to the book by Chartrand and Lesniak [
1].
An antimagic labeling of a graph is a bijection f from the set of edges of G to the integers such that all vertex-weights are pairwise distinct, where a vertex-weight is the sum of labels of all edges incident with that vertex, i.e., for the vertex the weight . A graph is called antimagic if it admits an antimagic labeling.
The concept of
antimagic labeling was introduced by Hartsfield and Ringel [
2] who conjectured that every simple connected graph, other than
, is antimagic. This conjecture is still open although for some special classes of graphs it was proved, see for instance [
3,
4,
5,
6,
7,
8]. Alon et al. [
9] proved that large dense graphs are antimagic. Hefetz et al. [
10] proved that any graph on
vertices that admits a
-factor, where
p is an odd prime and
k is a positive integer, is antimagic. Perhaps the most remarkable result to date is the proof for regular graphs of odd degree given by Cranston et al. in [
11], which was subsequently adapted to regular graphs of even degree by Bércz et al. in [
12] and by Chang et al. in [
13].
Recently, two groups of authors in [
14,
15] independently introduced a
local antimagic labeling as local version of the Hartsfield and Ringel’s concept of antimagic labeling. An edge labeling using every label from the set
exactly once is a
local antimagic labeling if the vertex-weights
and
are distinct for every pair of neighboring vertices
u,
v.
In [
14] authors conjectured that any connected graph other than
admits a
local antimagic labeling. Bensmail et al. [
15] propose the slightly stronger form of the previous conjecture that every graph without component isomorphic to
has a
local antimagic labeling. This conjecture was proved by Haslegrave [
16] using the probabilistic method.
Any
local antimagic labeling induces a proper vertex coloring of
G where the vertex-weight
is the color of
u. This naturally leads to the concept of a local antimagic chromatic number introduced in [
14]. The
local antimagic chromatic number is defined to be the minimum number of colors taken over all colorings of
G induced by
local antimagic labelings of
G.
For any graph
G,
, where
is the chromatic number of
G as the minimum number of colors needed to produce a proper coloring of
G. In [
14] is investigated the local antimagic chromatic number for paths, cycles, friendship graphs, wheels and complete bipartite graphs. Moreover, there is proved that for any tree
T with
l leaves
.
In this paper, we investigate the local antimagic chromatic number for disjoint union of multiple copies of a graph G, denoted by , , and we present some estimations of this parameter.
Please note that G does not have to be necessarily connected. By the symbol we denote the element (vertex or edge) corresponding to the element (vertex or edge) x in the ith copy of G in , .
2. Graphs with Vertices of Even Degrees
A graph G is called equally 2-edge colorable if it is possible to color its edges with two colors , such that for every vertex the number of edges incident to the vertex v colored with color is the same as the number of edges incident to the vertex v colored with color . This means that for any vertex is , where denotes the number of edges incident to the vertex v and colored with color , . Trivially, if a graph G is equally 2-edge colorable then all vertices in G have even degrees.
Consider that G is an even regular graph. Then there exists an Euler circle in G. If we alternatively color the edges in the Euler circle with colors and we obtain that either for every vertex v in G holds , or there exists exactly one vertex in G, say w, such that .
Consider a 2-edge coloring c of a graph G. Let denote the number of vertices in G such that under the labeling c. In this case we say that c is a -equally 2-edge coloring of G.
Let
c be any 2-edge coloring of
G. Let
f be any bijective mapping in
G,
. We define an edge labeling
g of
,
in the following way
If an edge in G is labeled with the number t, , then the corresponding edges in are labeled with numbers from the set . Thus we immediately obtain that the labeling g is a bijective mapping that assigns numbers to the edges of .
Moreover, for the weight of the vertex
,
, in
under the labeling
g we obtain the following
Thus, for every vertex
such that
we obtain
for
. This means that the corresponding vertices in different copies have the same weights. Summarizing the previous we obtain the following lemma that will be used later.
Lemma 1. Let G be a graph and let c be a 2-edge coloring of G and let f, , be a bijection. Let m, , be a positive integer. Then there exists an edge labeling g of such that the weights of vertices , , corresponding to the vertex satisfying will be the same.
Immediately from the previous result we obtain the following theorem for equally 2-edge colorable graphs.
Theorem 1. Let m be a positive integer. Let G be an equally 2
-edge colorable graph and let f be a local vertex antimagic edge labeling of G that uses colors. Let for every edge beThen Proof. Let f be a local vertex antimagic edge labeling of G that uses colors. Let c be an equally 2-edge coloring of G. This means that for every vertex is .
According to Lemma 1 and Equality (
1) we obtain that there exists a labeling
g of
,
, such that for every
and every
holds
. Thus,
g is such labeling that the corresponding vertices in different copies have the same weights. If for all adjacent vertices
holds
then also all adjacent vertices in
have distinct weights.
Moreover, . This concludes the proof. □
Note, if
G is a regular graph then the condition (
2) trivially holds. Results in the next two theorems are based on the Petersen Theorem.
Proposition 1. (Petersen Theorem) Let G be a -regular graph. Then there exists a 2-factor in G.
Notice that after removing edges of the 2-factor guaranteed by Petersen Theorem we have again an even regular graph. Thus, by induction, an even regular graph has a 2-factorization.
Theorem 2. Let G be a -regular graph, . Then for every positive integer m Proof. Let
G be a
-regular graph. According to Petersen Theorem
G is decomposable into 2-factors
. Consider an edge coloring
c of
G defined such that
Evidently,
c is an equally 2-edge coloring of
G. Thus, immediately according to Theorem 1 we obtain the desired result. □
Theorem 3. Let G be a -regular graph, , containing a 2
-factor consisting only from even cycles. Then for every positive integer m Proof. Let G be a -regular graph containing a 2-factor consisting only from even cycles. Denote this 2-factor by . Let us denote the edges in component by the symbols arbitrarily in such a way that all cycles in are of the form , where are odd integers. As all cycles in are even, evidently every vertex in G is incident with an edge in with an even and also with an odd index.
According to Petersen Theorem the graph
is decomposable into 2-factors
. Consider an edge coloring
c of
G defined such that
It is easy to see that for every vertex
holds
This means that
c is an equally 2-edge coloring of
G. By Theorem 1 we obtain that
. □
Corollary 1. Let n, m be positive integers, , . Then Proof. In [
14] it was proved that
for every
. According to Theorem 3 we obtain that if
then for every positive integer
m holds
.
Now suppose there exists a
local antimagic labeling f that induces a 2-coloring
of
, i.e., the set of the vertex weights consists of two numbers
and
. As every edge label contributes exactly once to the vertex weight of a vertex colored
we obtain
However, every edge label contributes also exactly once to the vertex weight of a vertex colored
thus
A contradiction. Thus,
. □
Theorem 4. Let n, m be positive integers, , . Then Proof. Let us denote the vertex set and the edge set of such that and . Let , , and let , .
We define an edge labeling
f of
in the following way
For the weight of the vertex
,
,
we obtain
and for
,
, we obtain
The weight of the vertex
,
, is
thus the weights are
. Thus, all adjacent vertices have distinct weights. Moreover we obtain
. □
Please note that a cycle
is 1-equally 2-edge colorable. It is possible to generalize the results from the previous section also for
-equally 2-edge colorable graphs. If we are able to guarantee that for every edge
is
then we can prove that
This condition is fulfilled for some graphs containing pendant vertices, thus also for some trees.
Lemma 2. Let G be a graph with l leaves, . Then Proof. The proof is similar to the proof in [
14]. Let
f be any
local antimagic labeling of a graph
G. Then in the coloring induced by
f, the color of a leaf
v is
, where
. Hence all the leaves receive distinct colors. Moreover, for any non-leaf
w incident with an edge
e with
, the color assigned to
w is larger than
. Hence the number of colors in the coloring induced by
f is at least
. □
Theorem 5. Let G be a graph without a component isomorphic to such that all vertices in G but leaves have the same even degree. If there exists a 2
-edge coloring c of G such that for all vertices v but leaves holds , thenwhere m is a positive integer and l is the number of leaves in G. Proof. Let G be a graph without a component isomorphic to such that all its vertices but leaves have the same even degree . Let c be a 2-edge coloring of G such that for all vertices v in G but leaves holds .
Let
f be any
local antimagic labeling of a graph
G that uses
colors. Then using Equality (
1) we obtain that there exists an edge labeling
g of
,
, such that the weights of non-leaf vertices
,
, corresponding to a vertex
v in
G, are
This means that the weights of corresponding non-leaf vertices in every copy of
G are the same. However, this also means that the adjacent non-leaf vertices in
have distinct weights.
Now consider the edges
,
, where
w is a leaf. For
trivially holds
Which means that all adjacent vertices have distinct weights.
Combining the previous arguments we obtain
The lower bound for
follows from Lemma 2. □
3. Trees
If the graph in Theorem 5 is a forest we immediately obtain the following result.
Theorem 6. Let T be a forest with no component isomorphic to such that all vertices but leaves have the same even degree. Thenwhere m is a positive integer and l is the number of leaves in T. Proof. Trivially, any graph containing as a component cannot be local antimagic.
Let T be a forest with no component isomorphic to such that all vertices but leaves have the same even degree . Clearly there exists a 2-edge coloring c of T such that for all vertices v but leaves hold . Thus, according to Theorem 5 we are done. □
Immediately from the previous theorem we obtain the result for copies of paths and copies of some stars as
for
and
for
, see [
14].
Corollary 2. Let be a path on n vertices, . Then for every positive integer m, , holds Corollary 3. Let be a star, . Then for every positive integer m, , holds Theorem 7. Let be a star, . Then for every positive integer m, , holds Proof. Let us denote the vertices and the edges of
such that
We consider two cases according to the parity of
m.
Case 1: when m is odd.
We define an edge labeling
g of
in the following way
Evidently
g is a bijection and the induced weights of the vertices
,
, are
As all vertices of degree
have the same weights and the weights of the leaves are distinct we obtain
. The lower bound follows from Lemma 2.
Case 2: when m is even.
In this case consider a labeling
f of
defined such that
According to the properties of the labeling
g, the labeling
f is a bijective mapping that assigns numbers
to the edges of
. The weights of vertices
,
, are all the same as
The weight of the vertex
is
If the weight of the vertex
under the labeling
f is the same as the weight of some leaf, we obtain that
. This is satisfied when
, that is if
. The equality
holds because the number of induced colors must be greater then the number of leaves, see Lemma 2.
Now consider that the weight of the vertex under the labeling f is greater then the weight of all leaves, i.e., . Then labeling f induces colors for vertices.
To prove that it is not possible to obtain
colors it is sufficient to consider the fact, that the weight of any vertex of degree
is at least the sum of numbers
, thus it is at least
. However, the weights of leaves are at most
. Thus if there exists an edge labeling that induces
colors for vertices, under this labeling all vertices
,
must have the same color/weight, say
. However, in this case the sum of all edge labels must be equal to
m multiple of
, as every edge label contributes exactly once the weight of a vertex of degree
. Thus
which implies
However, this is a contradiction as for
m even the right side of the previous equation is odd. This means that in this case
. □
Please note that Theorem 6 can be extended also for other trees (forests) such that their non-leaf vertices have even degrees, not necessarily the same. We just need to guarantee that the adjacent non-leaf vertices will have distinct weights. For some trees, for example for spiders, we are able to do it. A
spider graph is a tree with exactly one vertex of degree greater than 2. By
,
,
,
, we denote a spider obtained by identifying one leaf in paths
,
. In [
17] was proved that if
then
and if
then
. Moreover, for
the described edge labeling induces for the root vertex, the vertex of degree
l, the largest weight over all other vertex weights. Using the presented results we obtain
Theorem 8. Let be a spider graph. If l is even, , and If l is even, , and In [
18] was proposed the following conjecture.
Theorem 9. Ref. [
18]
Let T be a tree other than with l leaves. Then In the light of the previous results trees, for copies of trees we conjecture
Theorem 10. Let T be a tree other than with l leaves. Then for every positive integer m, , 4. Graphs with Chromatic Index 3
In this section we will deal with 3-regular graphs that admit a proper 3-edge coloring.
Theorem 11. Let G be a 3
-regular graph with chromatic index . Then for every odd positive integer m, , holds Proof. Let c be a proper 3-edge coloring of G. Let f be a local vertex antimagic edge labeling of G that uses colors.
We define a new labeling
g of
, for
m odd, in the following way.
It is easy to see that if an edge in
G is labeled with the number
t,
, then the corresponding edges in
are labeled with numbers from the set
. Thus,
g is a bijection that assigns numbers
to the edges of
.
Now we will calculate a vertex weight of the vertex
in
. Let
and
z be the vertices adjacent to
v in
G. Without loss of generality we can assume that
,
and
. Then for
we obtain
If
then
Thus, in all copies the corresponding vertices have the same weights.
Moreover, as the set of weights of vertices in G under the labeling f consists of distinct numbers we immediately obtain that also the set of weights of vertices in under the labeling g consists of distinct numbers. Thus, . □
Analogously, as it was possible to extend the results in
Section 2 for graphs with leaves, we can also extend Theorem 11 for some graphs with pendant vertices.
Theorem 12. Let G be a graph such that all vertices but leaves have degree 3
. If there exists a 3
-edge coloring c of G such that for all vertices v but leaves hold , then for every odd positive integer m, ,where l is the number of leaves in G. Proof. Let G be a graph such that all its vertices but leaves have degree 3. Let c be a 3-edge coloring of G such that for all vertices v in G but leaves hold .
Let
f be any
local antimagic labeling of a graph
G that uses
colors. Then using Equality (
4) we obtain that there exists an edge labeling
g of
,
m odd
, such that the weights of non-leaf vertices
,
, corresponding to a vertex
v in
G, are
This means that the weights of corresponding non-leaf vertices in every copy of
G are the same. However, this also means that the adjacent non-leaf vertices in
have distinct weights.
Now consider the edges
,
, where
w is a leaf. Trivially holds
Which means that all adjacent vertices have distinct weights.
Combining the previous arguments we obtain
The lower bound for
follows from Lemma 2. □
Immediately for forests we obtain the following result.
Corollary 4. Let T be a forest such that all its vertices but leaves have degree 3
. Then for every odd positive integer m, holdswhere l is the number of leaves in T. Proof. Let T be a forest such that all its vertices but leaves have degree 3. Trivially there exists a 3-edge coloring c of T such that for all vertices v but leaves hold . Using Theorem 12 we obtain the desired result. □
The next theorem shows how it is possible to extend the previous result for regular graphs that are decomposable into spanning subgraphs that are all isomorphic either to even regular graphs or 3-regular graphs.
Theorem 13. Let G be a graph that can be decomposed into factors , , and let every factor , , be isomorphic to a graph of the following types:
type I: a 4-regular graph,
type II: a 2-regular graph consisting of even cycles,
type III: a 3-regular graph with chromatic index 3.
If every factor , , is of type I or of type II then for every positive integer m, , holdsIf at least one factor , , is of type III then for every odd positive integer m, , holds Please note that the exact value of is n, since . Immediately from the previous theorem we obtain the following result for complete graphs .
Corollary 5. Let be a complete graph on n vertices, . If then for every positive integer m, , and if then for every odd positive integer m, , we have .