1. Introduction
Let
be a complex variable, and
the set of all prime numbers. The Riemann zeta function
is defined, in the half-plane
, by
or by the infinite Euler product
and has analytic continuation to the whole complex plane, except for a simple pole at the point
with residue 1.
The function
is a significant analytic object which is used not only in many branches of mathematics, but also in solving problems in other natural sciences, see, for example, [
1,
2,
3]. This is due to deep connections between
and objects of arithmetic, analytic and probabilistic character. It is not surprising that the function
has a certain link to the famous mathematician and philosopher Pythagoras, who was not only a geometer but also the founder of mathematical philosophy. He saw mathematics everywhere, and said that all things are numbers, and began to use mathematics in astronomy and even music. Since the function
is the main tool for the investigation of numbers, and has unexpected results even in cosmology and music (tuning problem), the theory of
supports and develops the Pythagorean philosophy. Last time, applications of
crossed the threshold of numbers, and the function
became universal among functions. This paper is devoted to approximation problems of analytic functions by shifts
, and is a continuation of the works in [
4,
5]. We recall that a possibility of the approximation of a class of functions by shifts of one and the same function is called universality, and was found by S.M. Voronin in [
6], see also [
7,
8]. The discrete variant of the Voronin theorem was proposed by A. Reich in [
9]. Let
, and let
stand for the set of compact sets lying in
and having connected complements. Moreover, denote by
,
the set of non-vanishing continuous functions on
, which are analytic inside of
K. Let
stand for the cardinality of the set
A, and let
. Then, the last discrete version of the Voronin universality theorem is the following statement [
9]. For all
,
, and positive
h and
,
In [
10], we began to consider the joint approximation of analytic functions by shifts
, where
is the sequence of Gram numbers. Let
be the gamma function. Then, the function
has the functional equation
Let
,
be the increment of the argument of the product
along the segment which connect the points
and
. Since the function
increases and is unbounded from above for
, the equation
has the unique solution
for
. J.P. Gram was the first to consider the points
in connection to non-trivial zeros
of the function
[
11], therefore they are called Gram points. More information on Gram points can be found in [
12,
13,
14]. Equation (
1) is also considered with arbitrary real
in place of
n. In this case, we have the Gram function
.
In [
10], we obtained a joint universality theorem on the approximation of analytic functions by shifts
with different fixed positive numbers
. The latter theorem was extended to short intervals in [
4]. The paper in [
5] is devoted to the discrete version of the results of [
10].
Theorem 1 ([
5])
. Let be fixed different positive numbers not exceeding 1, and for , and . Then, for any ,Moreover, the lower limit can be replaced by the limit for all but at most countably many .
Keeping in mind the effectivization of Theorem 1, we prove in this paper a version of Theorem 1 in short intervals. Without a loss of generality, we may suppose that
. For brevity, we set
where
. Moreover, we use the notation
. The objective of the paper is to prove that the set of approximating shifts
in Theorem 1 has a positive lower density for every
(and a positive density for all but at most countably many
) for
k in the interval
.
The paper is organized in the following way: In
Section 2, some mean square estimates for the function
in short intervals are obtained.
Section 3 is devoted to a joint discrete limit theorem in short intervals on weakly convergent probability measures in
r-dimensional space of analytic functions. Finally, in
Section 4, we prove the main theorem.
2. Some Estimates
It is well known that mean square estimates occupy a central place in the proofs of universality theorems on the approximation of analytic functions by zeta functions. This, in a more complicated form, also takes place in the case of short intervals. Recall that the notation , , means the existence of a constant such that .
We start with recalling a mean square estimate for the function in short intervals.
Lemma 1. Suppose that is fixed, and . Then, uniformly in H, Proof. Suppose that the exponential pair
and
are connected by the inequality
, and
. Then, Theorem 7.1 of [
15] asserts that, uniformly in
H,
Therefore, the exponential pair gives the lemma. □
For the proof of a discrete limit theorem for the function twisted by Gram points in short intervals, we need the corresponding mean square estimate. Unfortunately, we do not know a discrete version of Lemma 1. Therefore, we will derive the desired estimate from a continuous one which is contained in the next lemma.
Lemma 2. Suppose that and are fixed, , and . Then, Proof. It is known [
12] that, for
,
and
Thus, since
, the function
is decreasing for large
. Hence,
where
. In view of the hypotheses for
H,
Therefore, by Lemma 1, and if
, then, by (
4),
It is well known that, for
,
If
, then
, and
. Thus, by (
6), if
, then
This and (
5) prove the lemma. □
The next lemma (Gallagher lemma) together with Lemma 2 will imply the bound for the discrete mean square.
Lemma 3 ([
16])
. Suppose that , is a finite non-empty set in the interval , andLet a complex valued function be continuous on and have a continuous derivative on . Then, Unfortunately, an application of Lemma 3 requires the restriction .
Lemma 4. Suppose that and are fixed, , and . Then, Proof. We take in Lemma 3
,
,
and
. Obviously,
. Therefore, an application of Lemma 3 with the function
yields
The Cauchy integral formula gives
where
L is a circle
lying in the strip
. Therefore,
The latter estimate, and (
7) and (
8) prove the lemma. □
Now we are ready to approximate
by an absolutely convergent Dirichlet series. Let
be a fixed number, and
Then the series
is absolutely convergent for
with arbitrary finite
.
Lemma 5. Suppose that is a compact set, and . Then, Proof. The Mellin formula
implies the integral representation, see, for example, [
17],
where
. There exists
such that
for
. The integrand in (
9) has simple poles at
and
. Therefore, taking
and
, we find by the residue theorem
Thus, for all
,
in virtue of a shift
. Hence,
It is well known that, for large
, the estimate
with
, uniformly in
in any interval
,
, is valid. Therefore, for all
,
with
. Thus, by (
11),
To estimate
, we observe that (
12), for all
, implies the bound
with
. Hence, in view of (
2),
with positive
and
. This, (
13) and (
10) show that
Now, taking , and then , we obtain the equality of the lemma. □
3. Weak Convergence
Let
be a certain topological space with the Borel
-field
, and
P and
,
, probability measures on
. By the definition,
converges weakly to
P as
, (
) if
for every real bounded continuous function
g on
. In this section, we will obtain the weak convergence for some measures in the space of analytic functions. Denote by
the space of analytic on
functions endowed with the topology of uniform convergence on compacta, and set
For
, define
where
,
, and
We consider the weak convergence of as , where .
For the definition of the limit measure, we need some notation. Define the Cartesian product
The infinite-dimensional torus
equipped with the product topology and operation of pointwise multiplication becomes a compact topological Abelian group; therefore,
where
for
, again is a compact topological group. Hence, the probability Haar measure
on the space
exits, and we arrive to the probability space
. For
, let
and
be the element of
. Now, on the above probability space, define the
-valued random element
The latter infinite products, for almost all
, converge uniformly on compact sets of the strip
[
17]. Let
i.e.,
is the distribution of
. Now we state a limit theorem for
.
Theorem 2. Suppose that , and . Then, .
Before the proof of Theorem 2, we prove several separate lemmas. First of them is devoted to the space
. For
, set
Lemma 6. Suppose that , and . Then .
Proof. On groups, it is convenient to apply the Fourier transform method. Let
,
,
, be the Fourier transform of
. It is well known that
where the star “
” shows that only a finite number of integers
are distinct from zero. Thus, the definition of
implies
Clearly,
where
.
Now suppose that
. Then there exists at least one
, such that
. Since the set
is linearly independent over the field of rational numbers,
for such
j. Let
be the largest of
j with
. Hence,
and
in view of (
2) and (
3). For the estimation the sum (
14), we apply a representation of trigonometric sums by integrals, see, for example, [
18]. Suppose that the real-valued function
has a monotonic derivative on
, such that
. Then,
Relation (
16) shows that the function
, for sufficiently large
N, satisfies the above requirements on
. Thus, by (
14) and (
17),
with
Moreover, by the mean value theorem and (
16),
and
Therefore, by (
18), for sufficiently large
N,
By the hypotheses for
M and (
2) and (
3),
This, together with (
15), shows that
and the lemma is proved because the right-hand side of the latter equality is the Fourier transform of the measure
. □
Lemma 6 implies the weak convergence for
as
, where
Define the mapping
by
with
and
Then the measure
on
defines the unique probability measure
on
, where
Lemma 7. Under hypotheses of Lemma 6, .
Proof. Since the series for
converges absolutely for
, the mapping
is continuous. Moreover,
The latter equality, Lemma 6, the continuity of
and the well-known property of preservation of the weak convergence, see, for example, Theorem 2.7 of [
19], prove the lemma. □
The weak convergence of the measure is very important for that of . The following statement is true:
Lemma 8 ([
10])
. The relation holds. To prove Theorem 2, we need one statement on convergence in distribution of random elements. Let , , and X be -valued random elements. Recall that as converges to X in distribution () if the distribution of converges weakly to the distribution of X.
Lemma 9 ([
19])
. Suppose that the space is separable, and the -valued random elements and , are defined on the same probability space . If and for every , then also . Before the proof of Theorem 2, recall the metric in the space
. There exists a sequence
of embedded compact subsets such that the union of the sets
is the region
, and, for every compact set
, there exists
,
. Taking
gives a metric in
inducing the topology of uniform convergence on compacta. Then,
is a metric in
which induces its product topology.
Proof of Theorem 2. Denote by
the
-valued random element with distribution
. Then, by Lemma 8, we have
Let
be a random variable on a certain probability space with measure
P with the distribution
Define two
-valued random elements
and
Lemma 7 implies the relation
From the definitions of the metrics
d and
, and Lemma 5, it follows that
Therefore, the definitions of
and
, together with Chebyshev’s type inequality, give, for every
,
This, (
20) and (
21) show that all hypotheses of Lemma 9 are satisfied. Thus,
and the theorem is proved. □
4. Main Theorem
The main result of the paper is the following theorem:
Theorem 3. Suppose that are different fixed positive numbers not exceeding 1, and . For , let and . Then, for every , Moreover, the lower limit can be replaced by the limit for all but at most countably many .
Theorem 3 easily follows from Theorem 2 and the Mergelyan theorem on the approximation of analytic functions by polynomials [
20].
Let
P be a probability measure on
, and the space
is separable. Recall that the support of the measure
P is a minimal closed set
such that
. The set
consists of all
such that, for every open neighbourhood
G of
x, the inequality
is satisfied. Let
, and
Lemma 10 ([
10])
. The support of the measure is the set . Proof of Theorem 3. By the Mergelyan theorem, there exist polynomials
such that
In view of Lemma 10,
is an element of the support of the measure
. Therefore,
is an open neighbourhood of an element of the support, hence, we have
From this, using Theorem 2 and the equivalent of weak convergence in terms of open sets, see, for example, Theorem 2.1 of [
19], we find
This, the definitions of
and
, and inequality (
22) prove the first assertion of the theorem.
To prove the second assertion of the theorem, define one more set
Then the boundaries
and
do not intersect for different positive
and
. Hence, the set
is a continuity set of the measure
, i.e.,
, for all but at most countably many
. Therefore, by Theorem 2 and the equivalent of weak convergence in terms of continuity set, see, for example, Theorem 2.1 of [
19], we have
for all but at most countably many
. In view of (
22), the inclusion
holds. Therefore, by (
23), the inequality
is valid. This, (
24) and the definitions of
and
prove the second assertion of the theorem. □
Theorem 3 is stronger than Theorem 1 because the numbers k for which has the approximating property of analytic functions lie in the interval of length M, which may be taken as .
5. Conclusions
Let be a sequence of Gram points, and fixed numbers. In this paper, it is obtained that the interval with contains infinitely many , such that the shifts approximate every collection of analytics in non-vanishing functions.
The problems for future studies are the following:
To remove the requirement ;
To decrease the lower bound for .