A New Explicit Four-Step Symmetric Method for Solving Schrödinger’s Equation
Abstract
:1. Introduction
2. Preliminaries
3. Method Development
4. Error and Stability Analysis
4.1. Comparative Error Analysis
- Case 1. , i.e., the energy, E, is close to the potential . Therefore, in comparing the LTEs in these methods only the terms free of G are considered. Hence, for these terms all the methods are of comparable accuracy, as all their terms free of G are identical.
- Case 2. , that is is considerably large.
4.2. Stability Analysis
5. Numerical Results and Discussion
- The method of order eight produced in [22], which is denoted by .
- The method of order ten developed in [22], which is denoted by .
- The method of order eight developed in [22], which is denoted by .
- The four-step method produced in [26], which is denoted by .
- The four-step method developed in [29], which is denoted by .
- The method presented in [30], which is denoted by .
- The method developed in [31], which is denoted by .
- The method produced in [20], which is denoted by .
- The method developed in [32], which is denoted by .
- The method produced in [21], which is denoted by .
- The four-step classical method described in Section 2, which is denoted by .
6. Conclusions
Author Contributions
Funding
Acknowledgments
Conflicts of Interest
References
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Obaidat, S.; Mesloub, S. A New Explicit Four-Step Symmetric Method for Solving Schrödinger’s Equation. Mathematics 2019, 7, 1124. https://doi.org/10.3390/math7111124
Obaidat S, Mesloub S. A New Explicit Four-Step Symmetric Method for Solving Schrödinger’s Equation. Mathematics. 2019; 7(11):1124. https://doi.org/10.3390/math7111124
Chicago/Turabian StyleObaidat, Saleem, and Said Mesloub. 2019. "A New Explicit Four-Step Symmetric Method for Solving Schrödinger’s Equation" Mathematics 7, no. 11: 1124. https://doi.org/10.3390/math7111124
APA StyleObaidat, S., & Mesloub, S. (2019). A New Explicit Four-Step Symmetric Method for Solving Schrödinger’s Equation. Mathematics, 7(11), 1124. https://doi.org/10.3390/math7111124